golang中单个数组中的多重响应
multiple response in single array in golang
我是 golang 的新手。我想得到多重结果的回应。我做了一些方法,但我需要改变那个
impartErrl := ph.profileService.ValidateSchema(gojsonschema.NewStringLoader(string(b)))
if impartErrl != nil {
ctx.JSON(http.StatusBadRequest, impart.ErrorResponse(impartErrl))
return
}
func (ps *profileService) ValidateSchema(document gojsonschema.JSONLoader) (errors []impart.Error) {
result, err := gojsonschema.Validate(ps.schemaValidator, document)
if err != nil {
ps.SugaredLogger.Error(err.Error())
return impart.ErrorResponse(
impart.NewError(impart.ErrBadRequest, "unable to validate schema"),
)
}
if result.Valid() {
return nil
}
// msg := fmt.Sprintf("%v validations errors.\n", len(result.Errors()))
msg := "validations errors"
for i, desc := range result.Errors() {
msg += fmt.Sprintf("%v: %s\n", i, desc)
er := impart.NewError(impart.ErrValidationError, fmt.Sprintf("%s ", desc), impart.ErrorKey(desc.Field()))
errors = append(errors, er)
}
return errors
}
func NewError(err error, msg string, args ...interface{}) Error {
key := GetErrorKey(args...)
return impartError{
err: err,
msg: msg,
key: key,
}
}
func ErrorResponse(err interface{}) []Error {
var errorResponse []Error
switch err.(type) {
case Error:
errorResponse = []Error{err.(Error)}
case []Error:
errorResponse = err.([]Error)
default:
errorResponse = []Error{
NewError(ErrUnknown, fmt.Sprintf("%v", err)),
}
}
return errorResponse
}
type Error interface {
error
HttpStatus() int
ToJson() string
Err() error
Msg() string
}
现在我得到的输出是
[
{
"error": "validation error",
"msg": "email: Does not match format 'email' ",
"key": "email"
},
{
"error": "validation error",
"msg": "screenName: String length must be greater than or equal to 4 ",
"key": "screenName"
}
]
但我需要我的回应
{
0 :{
"error": "validation error",
"msg": "email: Does not match format 'email' ",
"key": "email"
},
1 : {
"error": "unable to complete the request",
"msg": "invalid screen name, must be alphanumeric characters only",
"key": "screen_name"
}
}
我怎样才能得到这些类型的响应。 ?因为在 ios 应用中解析响应 [] 时显示错误。所以我需要更改输出。
请帮助我。
ErrorResponse
函数应该 return 一个 map[int]Error
而不是 []Error
。例如:
func ErrorResponse(err interface{}) map[int]Error {
errorResponse := map[int]Error{}
switch e := err.(type) {
case Error:
errorResponse[0] = e
case []Error:
for i, k := range e {
errorResponse[i] = k
}
default:
errorResponse[0] = NewError(ErrUnknown, fmt.Sprintf("%v", err))
}
return errorResponse
}
我是 golang 的新手。我想得到多重结果的回应。我做了一些方法,但我需要改变那个
impartErrl := ph.profileService.ValidateSchema(gojsonschema.NewStringLoader(string(b)))
if impartErrl != nil {
ctx.JSON(http.StatusBadRequest, impart.ErrorResponse(impartErrl))
return
}
func (ps *profileService) ValidateSchema(document gojsonschema.JSONLoader) (errors []impart.Error) {
result, err := gojsonschema.Validate(ps.schemaValidator, document)
if err != nil {
ps.SugaredLogger.Error(err.Error())
return impart.ErrorResponse(
impart.NewError(impart.ErrBadRequest, "unable to validate schema"),
)
}
if result.Valid() {
return nil
}
// msg := fmt.Sprintf("%v validations errors.\n", len(result.Errors()))
msg := "validations errors"
for i, desc := range result.Errors() {
msg += fmt.Sprintf("%v: %s\n", i, desc)
er := impart.NewError(impart.ErrValidationError, fmt.Sprintf("%s ", desc), impart.ErrorKey(desc.Field()))
errors = append(errors, er)
}
return errors
}
func NewError(err error, msg string, args ...interface{}) Error {
key := GetErrorKey(args...)
return impartError{
err: err,
msg: msg,
key: key,
}
}
func ErrorResponse(err interface{}) []Error {
var errorResponse []Error
switch err.(type) {
case Error:
errorResponse = []Error{err.(Error)}
case []Error:
errorResponse = err.([]Error)
default:
errorResponse = []Error{
NewError(ErrUnknown, fmt.Sprintf("%v", err)),
}
}
return errorResponse
}
type Error interface {
error
HttpStatus() int
ToJson() string
Err() error
Msg() string
}
现在我得到的输出是
[
{
"error": "validation error",
"msg": "email: Does not match format 'email' ",
"key": "email"
},
{
"error": "validation error",
"msg": "screenName: String length must be greater than or equal to 4 ",
"key": "screenName"
}
]
但我需要我的回应
{
0 :{
"error": "validation error",
"msg": "email: Does not match format 'email' ",
"key": "email"
},
1 : {
"error": "unable to complete the request",
"msg": "invalid screen name, must be alphanumeric characters only",
"key": "screen_name"
}
}
我怎样才能得到这些类型的响应。 ?因为在 ios 应用中解析响应 [] 时显示错误。所以我需要更改输出。
请帮助我。
ErrorResponse
函数应该 return 一个 map[int]Error
而不是 []Error
。例如:
func ErrorResponse(err interface{}) map[int]Error {
errorResponse := map[int]Error{}
switch e := err.(type) {
case Error:
errorResponse[0] = e
case []Error:
for i, k := range e {
errorResponse[i] = k
}
default:
errorResponse[0] = NewError(ErrUnknown, fmt.Sprintf("%v", err))
}
return errorResponse
}