PHP PDO 查询尝试从值创建子数组

Question

我想知道如何创建（子数组）？我不确定这是否是正确的术语，但我在下面列出了示例。

本质上，我想要每个度假村都有一个数组。在该数组中，我希望每个房间 array/sub-arrays。

感谢任何帮助。

<?php
$servername = "localhost";
$username = "root";
$password = "";

$dbh = new PDO("mysql:host=$servername;dbname=checkavail", $username, $password);

$checkin = $_POST['checkin'];
$checkout = $_POST['checkout'];
$occupants = $_POST['occupants'];
$sql=
"SELECT
MIN(staydate) AS checkin,
MAX(staydate) AS lastnight,
MIN(available) AS available,
ra.resort AS resortcode,
ri.resort AS resortname,
ri.room AS roomname,
ri.roomcode AS roomcode,
ri.view AS viewname,
SUM(ra.points) AS points,
ri.sqfoot AS sqfoot,
ri.description AS roomdescription,
ri.bedding AS bedding,
ri.amenities AS amenities,
ri.sleeps AS sleeps,
ri.sleep_details AS sleepdetails,
ri.layout_img AS layoutimg,
ri.room_img AS roomimg,
ri.roomimg_thumb AS roomimgthumb
FROM resort_availability AS ra
    LEFT JOIN room_info AS ri ON (ra.room = ri.roomcode)
WHERE staydate >= '$checkin' AND staydate < '$checkout'
AND sleeps >= '$occupants'
GROUP BY resortname, roomname
ORDER BY points
";
$result = $dbh->query($sql)->fetchAll(PDO::FETCH_ASSOC);



$return = [];
foreach ($result as $row) {
    $points = $row['points'];
    $price = $points*20;
    $pricefrmt = "$".number_format ($price, 2);
    $return[] = [ 
        'resort' => $row['resortname'],
        'room' => $row['roomname'],
        'price' => $pricefrmt
    ];
}
$dbh = null;

header('Content-type: application/json');
echo json_encode($return);
?>

这是当前输出：

[
  {
   "resort":"Resort1",
   "room":"DStudio",
   "price":",560.00"
  },
  {
   "resort":"Resort1",
   "room":"TVilla",
   "price":",980.00"
  },
  {
   "resort":"Resort1",
   "room":"1-Bedroom Villa",
   "price":",460.00"
  },
  {
   "resort":"Resort1",
   "room":"2-Bedroom LO Villa",
   "price":",040.00"
  },
  {
   "resort":"Resort1",
   "room":"2-Bedroom Villa",
   "price":",040.00"
  },
  {
   "resort":"Resort1",
   "room":"3-Bedroom Villa",
   "price":",620.00"
  },

  {
   "resort":"Resort2",
   "room":"DStudio",
   "price":",560.00"
  },
  {
   "resort":"Resort2",
   "room":"TVilla",
   "price":",980.00"
  },
  {
   "resort":"Resort2",
   "room":"1-Bedroom Villa",
   "price":",460.00"
  },
  {
   "resort":"Resort2",
   "room":"2-Bedroom LO Villa",
   "price":",040.00"
  },
  {
   "resort":"Resort2",
   "room":"2-Bedroom Villa",
   "price":",040.00"
  },
  {
   "resort":"Resort2",
   "room":"3-Bedroom Villa",
   "price":",620.00"
  }
]

但我希望它看起来更像这样...（如果格式看起来有点奇怪，那是因为我是菜鸟）

[
  {
    "resort":"Resort1"
    [
      {
       "room":"DStudio",
       "price":",560.00"
      },
      {
       "room":"TVilla",
       "price":",980.00"
      },
      {
       "room":"1-Bedroom Villa",
       "price":",460.00"
      },
      {
       "room":"2-Bedroom LO Villa",
       "price":",040.00"
      },
      {
       "room":"2-Bedroom Villa",
       "price":",040.00"
      },
      {
       "room":"3-Bedroom Villa",
       "price":",620.00"
      }
     ]
  }
  {
    "resort":"Resort2"
    [
      {
       "room":"DStudio",
       "price":",560.00"
      },
      {
       "room":"TVilla",
       "price":",980.00"
      },
      {
       "room":"1-Bedroom Villa",
       "price":",460.00"
      },
      {
       "room":"2-Bedroom LO Villa",
       "price":",040.00"
      },
      {
       "room":"2-Bedroom Villa",
       "price":",040.00"
      },
      {
       "room":"3-Bedroom Villa",
       "price":",620.00"
      }
     ]
  }
]

Answer 1

现在知道您创建了您提供的数组，我更正了您的原始代码以创建您想要的格式：

$result = $dbh->query($sql)->fetchAll(PDO::FETCH_ASSOC);



$return = [];
foreach ($result as $row) {
    $points = $row['points'];
    $price = $points*20;
    $pricefrmt = "$".number_format ($price, 2);
    # You dont need this code anymore:
    #    $return[] = [ 
    #    'resort' => $row['resortname'],
    #    'room' => $row['roomname'],
    #    'price' => $pricefrmt
    #];
    # Just this one line below is all you need
    $return[$row['resortname']][] = ['room' => $row['roomname'], 'price' => $pricefrmt];
}

我不确定您是否可以在 3 维数组中输出 DB table，但您确实可以像这样编辑当前输出：

# Declare new array
$newarr = [];

# Iterate through each of the second dimensional arrays as $arr
foreach($return as $arr){

    # Parse said data into the new array
    $newarr[$arr['resort']][] = array("room" => $arr['room'], "price" => $arr['price']);
}

JSON Output/Results:

{
    "Resort1": [
        {
            "room": "DStudio",
            "price": ",560.00"
        },
        {
            "room": "TVilla",
            "price": ",980.00"
        },
        {
            "room": "1-Bedroom Villa",
            "price": ",460.00"
        },
        {
            "room": "2-Bedroom LO Villa",
            "price": ",040.00"
        },
        {
            "room": "2-Bedroom Villa",
            "price": ",040.00"
        },
        {
            "room": "3-Bedroom Villa",
            "price": ",620.00"
        }
    ],
    "Resort2": [
        {
            "room": "DStudio",
            "price": ",560.00"
        },
        {
            "room": "TVilla",
            "price": ",980.00"
        },
        {
            "room": "1-Bedroom Villa",
            "price": ",460.00"
        },
        {
            "room": "2-Bedroom LO Villa",
            "price": ",040.00"
        },
        {
            "room": "2-Bedroom Villa",
            "price": ",040.00"
        },
        {
            "room": "3-Bedroom Villa",
            "price": ",620.00"
        }
    ]
}

现场演示：http://sandbox.onlinephpfunctions.com/code/98541684aea923463de76183c1e42898c1d47ca5

PHP PDO 查询尝试从值创建子数组

PHP PDO Query trying to create subarrays from value

php

mysql

arrays

json

pdo