根据列对行进行排序？

Question

我在 R 中有一个 csv，其中包含以下 table：

df1

Start	Efficiency	Start	Efficiency	End
9955	0	9955	25	5848
474909	0	474909	35	3948
90342	25			84384
94209	55			99393

我想用正确的效率替换对应于起始列的假零效率，以便我的最终结果如下所示：

df2

Start	Efficiency	End
9955	25	5848
474909	35	3948
90342	25	84384
94209	55	99393

df1 <- data.frame(
  Start = c("9955", "474909", "90342", "94209"),
  Efficiency = c("0", "0", "25", "55"), 
  Start = c("9955", "474909"),
  Efficiency = c("25", "35"), 
  End = c("5848", "3948", "84384", "99393"), stringsAsFactors = F)

df2 <- data.frame(
  Start = c("9955", "474909", "90342", "94209"),
  Efficiency = c("25", "35", "25", "55"),
  End = c("5848", "3948", "84384", "99393"), stringsAsFactors = F)

Answer 1

R 不喜欢具有相同名称的列，因此重复的列名称变为 Start.1 和 Efficiency.1。您可以将 0 值替换为 NA 并使用 coalesce.

library(dplyr)

df1 %>%
  mutate(across(contains('Efficiency'), na_if, 0)) %>%
  transmute(Start, Efficiency = coalesce(Efficiency, Efficiency.1))

#   Start Efficiency
#1   9955         25
#2 474909         35
#3  90342         25
#4  94209         55

根据列对行进行排序？

Sort rows based on columns?

csv

sorting

row

r

columnsorting