如何唯一标识django中的模型实例

How to uniquely identify a model instance in django

我有一个程序可以保存不同学校的图书记录我有一个学生模型,可以让每所学校从 excel 上传学生。然而,我得到一个错误,因为已经有两所学校分别有 form 1 form 2 和 form 3。它 returns MultipleObjectsReturned 错误。 将字段设置为唯一也不允许其他学校创建相同的类。 我如何能够唯一地识别每个实例 ok Klass 模型,所以它 returns 没有错误。

get() 返回了不止一个 Klass -- 它返回了 2 个!

class ImportStudentsResource(resources.ModelResource):
    school = fields.Field(attribute = 'school',column_name='school', widget=ForeignKeyWidget(School, 'name'))
    klass = fields.Field(attribute = 'klass',column_name='class', widget=ForeignKeyWidget(Klass, 'name'))
    stream = fields.Field(attribute = 'stream',column_name='stream', widget=ForeignKeyWidget(Stream, 'name'))
    class Meta:
        model = Student
        fields = ('school','student_id','name','year','klass','stream')
        import_id_fields = ('student_id',)
        import_order = ('school','student_id','name','year','klass','stream')

class uploadStudents(LoginRequiredMixin,View):
    context = {}
    def get(self,request):
        form = UploadStudentsForm()
        self.context['form'] = form
        return render(request,'libman/upload_student.html',self.context)

    def post(self, request):
        form = UploadStudentsForm(request.POST , request.FILES)
        data_set = Dataset()
        if form.is_valid():
            file = request.FILES['file']
            extension = file.name.split(".")[-1].lower()
            resource = ImportStudentsResource()
            if extension == 'csv':
                data = data_set.load(file.read().decode('utf-8'), format=extension)
            else:
                data = data_set.load(file.read(), format=extension)
            result = resource.import_data(data_set, dry_run=True, collect_failed_rows=True, raise_errors=True)
            if result.has_validation_errors() or result.has_errors():
                messages.success(request,f'Errors experienced during import.')
                print("error", result.invalid_rows)
                self.context['result'] = result
                return redirect('upload_students')                
            else:
                result = resource.import_data(data_set, dry_run=False, raise_errors=False)
                self.context['result'] = None
                messages.success(request,f'Students uploaded successfully.')                
        else:
            self.context['form'] = UploadStudentsForm()

        return render(request, 'libman/upload_student.html', self.context)

class Student(models.Model):
    school = models.ForeignKey(School, on_delete=models.CASCADE)
    name = models.CharField(max_length=200)
    now = datetime.datetime.now()
    YEAR = [(str(a), str(a)) for a in range(now.year-2, now.year+2)]
    year = models.CharField(max_length=4, choices = YEAR)
    student_id = models.CharField(max_length=20,unique=True)
    klass = models.ForeignKey(Klass,on_delete=models.CASCADE)
    stream = models.ForeignKey(Stream,on_delete=models.CASCADE)

导入数据时,逻辑无法唯一标识 'klass' 的唯一实例。您正在使用与 class 的外键关系的 'name' 属性,但是正如您所说,此 'name' 字段无法唯一标识 Klass 的实例,因此您得到 MultipleObjectsReturned错误。

解决方案是创建 ForeignKeyWidget 的子class,它使用可以唯一标识 Klass 的覆盖 get_queryset()。您将需要使用可以添加到查询中的附加参数。我猜 school_id 可能有效(但我不知道你的数据模型)。​​

class KlassForeignKeyWidget(widgets.ForeignKeyWidget):
    """
    Custom widget to lookup a Klass instance
    """
    def __init__(
        self,
        school_id,
        field="name",
        *args,
        **kwargs,
    ):
        super().__init__(self.model, field=field, *args, **kwargs)
        self.school_id = school_id

    def get_queryset(self, value, row, *args, **kwargs):
        return self.model.objects.filter(school_id=self.school_id)

然后您必须在您的资源中声明此自定义小部件:

class ImportStudentsResource(resources.ModelResource):

    def __init__(self, school_id):
        super().__init__()
        self.school_id = school_id

        self.fields["klass"] = fields.Field(
            attribute="klass",
            column_name="class",
            widget=myapp.widgets.KlassForeignKeyWidget(
                school_id,
            ),
        )

然后当你实例化 ImportStudentsResource .