Laravel 8 多条路线相同 Url

Question

美好的一天

我是 Laravel 的新手，我想创建一个拥有多个用户（学生、主管、HOD）的网站。我想知道是否有办法让所有用户拥有相同的 URL。以下是我用来尝试实现此目的的方法：

web.php

// Routes For Students
Route::group(['middleware' => ['auth', 'role:student']], function() {
    Route::get('/home', 'App\Http\Controllers\StudentController@index')->name('student');
    Route::get('/proposal', 'App\Http\Controllers\StudentController@proposal')->name('proposal');
    Route::get('/thesis', 'App\Http\Controllers\StudentController@thesis')->name('thesis');
});

// Routes For Supervisors
Route::group(['middleware' => ['auth', 'role:supervisor']], function() {
    Route::get('/home', 'App\Http\Controllers\supervisorController@index')->name('supervisor');
    Route::get('/proposal', 'App\Http\Controllers\supervisorController@proposal')->name('proposal');
    Route::get('/thesis', 'App\Http\Controllers\supervisorController@thesis')->name('thesis');
});

// Routes For HOD's
Route::group(['middleware' => ['auth', 'role:hod']], function() {
    Route::get('/home', 'App\Http\Controllers\hodController@index')->name('hod');
    Route::get('/proposal', 'App\Http\Controllers\hodController@proposal')->name('proposal');
    Route::get('/thesis', 'App\Http\Controllers\hodController@thesis')->name('thesis');
});

但是我注意到你不能有相同 URL 的路由，但我希望所有类型的用户在他们各自的主页、提案和论文页面上都具有相同的 URL。这可能吗？

如果您需要更多代码或更好的解释，请告诉我。

Answer 1

我建议只为所有这些路由添加一个前缀。这样你就不会得到任何重复的 uris。

如果你真的不想这样做，我还有另一种可能性，但你将无法保留路由名称。

基本上，使用可调用控制器重新路由到正确的 controller/action。

php artisan make:controller -i

Route::group(['middleware' => ['auth']], function () {
    Route::get('/home', 'App\Http\Controllers\MyInvokableController')->name('home');
    Route::get('/proposal', 'App\Http\Controllers\MyInvokableController')->name('proposal');
    Route::get('/thesis', 'App\Http\Controllers\MyInvokableController')->name('thesis');
});

<?php

namespace App\Http\Controllers;

use Illuminate\Http\Request;

class MyInvokableController extends Controller
{
    private $lookupArray = [
        'home'     => 'index',
        'proposal' => 'proposal',
        'thesis'   => 'thesis',
    ];

    public function __invoke(Request $request)
    {
        $role = ;// get your user's role
        $urlSegment = $request->segment(count($request->segments()) - 1); // 'home', 'proposal' or 'thesis'

        if ($role === 'student') {
            return app(StudentController::class)->{$this->lookupArray[$urlSegment]}($request);
        } elseif ($role === 'supervisor') {
            return app(supervisorController::class)->{$this->lookupArray[$urlSegment]}($request);
        } elseif ($role === 'hod') {
            return app(hodController::class)->{$this->lookupArray[$urlSegment]}($request);
        } else {
            throw new \Exception("Unexpected role $role.");
        }
    }
}

Answer 2

如果您需要保持相同的路线，您可以按照@IGP 的回答或只检查 blade 本身的用户角色。

// welcome.blade.php
@role('student')
    <h1>Student welcome page</h1>
@endrole

@role('supervisor')
    <h1>Supervisor welcome page</h1>
@endrole

@role('hod')
    <h1>Hod welcome page</h1>
@endrole

Answer 3

我认为你最好在控制器上处理逻辑而不是角色中间件。是否有主管担任学生“角色”？不，那是因为 Supervisor 在这里不是角色，而是用户类型。所以在这里你想要相同的URL，这是我更喜欢的：

Route::group(['middleware' => ['auth']], function() {
    Route::get('/home', 'App\Http\Controllers\Controller@index')->name('home');
    Route::get('/proposal', 'App\Http\Controllers\Controller@proposal')->name('proposal');
    Route::get('/thesis', 'App\Http\Controllers\Controller@thesis')->name('thesis');
});

在幕后处理用户类型。

public function index(Request $request) 
{
    // handle the request, determine the user type, populate the proper view, etc.
}

现在谈谈角色，

Middleware can also receive additional parameters. For example, if your application needs to verify that the authenticated user has a given "role" before performing a given action. Laravel 8 Documentation - Middleware

举个例子，您可以在您的应用程序中设置“演示者”角色，该角色具有唯一的 URL 并且允许学生和主管访问它们。

仅仅使用中间件并不意味着它就是一个有效的解决方案。正如文档所说：

Middleware provide a convenient mechanism for inspecting and filtering HTTP requests entering your application. Laravel Documentation

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