对 class 方法进行单元测试时,如何模拟它调用的函数——一个在导入模块中定义的函数?
When unit testing a class method, how do I mock a function it calls--one defined in an imported module?
我正在对特定方法进行单元测试,并且在模拟过程中调用的另一个函数时遇到问题。在我的例子中,要测试的方法是在 class 中定义的,而我想模拟的函数是在单独的模块中定义的。我如何模拟这个功能?请参阅下面的代码。
过去,我使用 Sinon 包来 mock/stub 依赖项 (example)。但这在这种情况下不起作用。这是我第一次测试 class 中定义的方法,所以也许这就是模拟依赖项不起作用的原因。
我的代码
包含测试函数的模块 (myLib/myDir/combo.js)
const { externalFunction } = require('./external-function')
class Combo {
constructor(props) {}
async myMethod () {// The function under test.
externalFunction()
}
}
const myCombo = props => new Combo(props)
module.exports = { myCombo }
我的测试文件(test/myLib/myDir/combo.test.js);没有尝试嘲笑
const { myCombo } = require('../../../myLib/myDir/combo')
const comboObj = myCombo({}) // Instantiate object to expose method to test.
await comboObj.myMethod()// Call method that I want to test. This throws type error because myMethod function calls externalFunction, which throws an error in the test environment.
我的测试文件(test/myLib/myDir/combo.test.js);尝试使用 Sinon 包来模拟
const sinon = require('sinon')
const dependencyModule = require('./external-function')// Defines the method dependencyModule.methodToMock
const myStub = sinon.stub(dependencyModule, 'methodToMock').returns(555) // Stubs dependencyModule.methodToMock and ensures it always returns the value: 555.
const comboObj = myCombo({}) // Instantiate object to expose method to test.
await comboObj.myMethod()// Call method that I want to test. This throws type error because myMethod function calls externalFunction, which throws an error in the test environment.
怎么做?您需要遵循“存根模块不能被解构”。在官方指南上 How to stub a dependency of a module
例如 我在同一个目录中有文件external-function.js、combo.js 和test.js。我选择使用 console.log 来显示存根有效并且调用了假函数,因为您不希望在 myMethod 上返回某些内容。
// File: external-function.js
function externalFunction () {
console.log('Original Called');
}
module.exports = { externalFunction };
// File: combo.js
// Note: "stubbed module can not be destructured."
const externalFunction = require('./external-function')
class Combo {
constructor(props) {}
async myMethod () {
externalFunction.externalFunction()
}
}
const myCombo = props => new Combo(props)
module.exports = { myCombo };
// File: test.js
const sinon = require('sinon');
const { myCombo } = require('./combo');
const dependencyModule = require('./external-function');
describe('myCombo', () => {
it('myMethod', async () => {
sinon.stub(dependencyModule, 'externalFunction').callsFake(() => {
console.log('Fake Called');
});
const comboObj = myCombo({});
await comboObj.myMethod();
});
});
当我 运行 它在我的终端上使用 nyc 和 mocha 时:
$ npx nyc mocha test.js
myCombo
Fake Called
✓ myMethod
1 passing (3ms)
----------------------|---------|----------|---------|---------|-------------------
File | % Stmts | % Branch | % Funcs | % Lines | Uncovered Line #s
----------------------|---------|----------|---------|---------|-------------------
All files | 85.71 | 100 | 75 | 83.33 |
combo.js | 100 | 100 | 100 | 100 |
external-function.js | 50 | 100 | 0 | 50 | 2
----------------------|---------|----------|---------|---------|-------------------
我正在对特定方法进行单元测试,并且在模拟过程中调用的另一个函数时遇到问题。在我的例子中,要测试的方法是在 class 中定义的,而我想模拟的函数是在单独的模块中定义的。我如何模拟这个功能?请参阅下面的代码。
过去,我使用 Sinon 包来 mock/stub 依赖项 (example)。但这在这种情况下不起作用。这是我第一次测试 class 中定义的方法,所以也许这就是模拟依赖项不起作用的原因。
我的代码
包含测试函数的模块 (myLib/myDir/combo.js)
const { externalFunction } = require('./external-function')
class Combo {
constructor(props) {}
async myMethod () {// The function under test.
externalFunction()
}
}
const myCombo = props => new Combo(props)
module.exports = { myCombo }
我的测试文件(test/myLib/myDir/combo.test.js);没有尝试嘲笑
const { myCombo } = require('../../../myLib/myDir/combo')
const comboObj = myCombo({}) // Instantiate object to expose method to test.
await comboObj.myMethod()// Call method that I want to test. This throws type error because myMethod function calls externalFunction, which throws an error in the test environment.
我的测试文件(test/myLib/myDir/combo.test.js);尝试使用 Sinon 包来模拟
const sinon = require('sinon')
const dependencyModule = require('./external-function')// Defines the method dependencyModule.methodToMock
const myStub = sinon.stub(dependencyModule, 'methodToMock').returns(555) // Stubs dependencyModule.methodToMock and ensures it always returns the value: 555.
const comboObj = myCombo({}) // Instantiate object to expose method to test.
await comboObj.myMethod()// Call method that I want to test. This throws type error because myMethod function calls externalFunction, which throws an error in the test environment.
怎么做?您需要遵循“存根模块不能被解构”。在官方指南上 How to stub a dependency of a module
例如 我在同一个目录中有文件external-function.js、combo.js 和test.js。我选择使用 console.log 来显示存根有效并且调用了假函数,因为您不希望在 myMethod 上返回某些内容。
// File: external-function.js
function externalFunction () {
console.log('Original Called');
}
module.exports = { externalFunction };
// File: combo.js
// Note: "stubbed module can not be destructured."
const externalFunction = require('./external-function')
class Combo {
constructor(props) {}
async myMethod () {
externalFunction.externalFunction()
}
}
const myCombo = props => new Combo(props)
module.exports = { myCombo };
// File: test.js
const sinon = require('sinon');
const { myCombo } = require('./combo');
const dependencyModule = require('./external-function');
describe('myCombo', () => {
it('myMethod', async () => {
sinon.stub(dependencyModule, 'externalFunction').callsFake(() => {
console.log('Fake Called');
});
const comboObj = myCombo({});
await comboObj.myMethod();
});
});
当我 运行 它在我的终端上使用 nyc 和 mocha 时:
$ npx nyc mocha test.js
myCombo
Fake Called
✓ myMethod
1 passing (3ms)
----------------------|---------|----------|---------|---------|-------------------
File | % Stmts | % Branch | % Funcs | % Lines | Uncovered Line #s
----------------------|---------|----------|---------|---------|-------------------
All files | 85.71 | 100 | 75 | 83.33 |
combo.js | 100 | 100 | 100 | 100 |
external-function.js | 50 | 100 | 0 | 50 | 2
----------------------|---------|----------|---------|---------|-------------------