URL 重写 QUERY_STRING NGINX？

Question

我想从最后一个地址有 x-oss-process 参数的主机下载任何文件。 i.php?path=$1&x-oss-process=%1 refer$1是被引用文件的地址，%1是x-oss-process参数的值喜欢下面的link

https://dl.example.com/img/all/235868.jpg?x-oss-process=image/resize,m_lfit,h_200,w_200/quality,q_60

将此地址引用到以下地址后

i.php?path=img/all/235868.jpg&x-oss-process=image/resize,m_lfit,h_200,w_200/quality,q_60

现在我该如何编写 nginx 代码来执行此操作？谢谢你的帮助。

Answer 1

如果查询参数名称不包含任何短划线字符，例如 x_oss_process 而不是 x-oss-process，解决方案会简单得多。在那种情况下，我们可以检查 $arg_x_oss_process 变量（参见 $arg_name 变量描述）：

if ($arg_x_oss_process) {
    rewrite ^ /i.php?path=$uri;
}

第一个参数^是匹配任意字符串的正则表达式，$uri is a normalized request URI (without query arguments). All the query arguments would be added to the rewrited URI (see the rewrite指令说明）：

If a replacement string includes the new request arguments, the previous request arguments are appended after them. If this is undesired, putting a question mark at the end of a replacement string avoids having them appended, for example:
rewrite ^/users/(.*)$ /show?user=? last;

然而，由于您的查询参数名称包含破折号，解决方案将更加复杂（请参阅 SO question for additional details). We would need to get the x-oss-process query argument value from $args variable using the map 指令，该指令应放置在外部 server 块:

map $args $x_oss_process {
    ~(?:^|&)x-oss-process=([^&]*)    ;
}

server {
    ...
    if ($x_oss_process) {
        rewrite ^ /i.php?path=$uri;
    }
    ...
}

此重写规则将重写

/img/all/235868.jpg?x-oss-process=image/resize,m_lfit,h_200,w_200/quality,q_60

请求

/i.php?path=/img/all/235868.jpg&x-oss-process=image/resize,m_lfit,h_200,w_200/quality,q_60

这与您要求的略有不同（请注意 img/all/235868.jpg URI 部分之前的斜杠）。我宁愿更改 i.php 脚本以正确处理它，但是如果你想用 nginx 本身去除这个斜线，你可以使用第二个 map 块：

map $args $x_oss_process {
    ~(?:^|&)x-oss-process=([^&]*)    ;
}
map $uri $truncated_uri {
    ~/(.*)                           ;
}

server {
    ...
    if ($x_oss_process) {
        rewrite ^ /i.php?path=$truncated_uri;
    }
    ...
}

URL 重写 QUERY_STRING NGINX？

URL rewriting QUERY_STRING NGINX?

nginx

query-string