处理 tictactoe 的异常情况

Question

我需要异常情况的帮助。我在下面提到了案例失败的地方。

possibleTurns = ("A1","A2","A3","B1","B2","B3","C1","C2","C3")
movesUsed = []

def main():    
    players = ["X","O"]
    while len(movesUsed) <9:
        #Player 1 Move
        turnp1 = input(f"Choose a move Player 1: ")
        print(f"Your move was: {turnp1}")
        validMove = analyzeMove(turnp1)
        move(validMove,players[0])
        score()
        movesUsed.append(validMove)
        #Player 2 Move
        turnp2 = input(f"Choose a move Player 2: ")
        print(f"Your move was: {turnp2}")
        validMove = analyzeMove(turnp2)
        move(validMove,players[1])
        score()
        movesUsed.append(validMove)```

def analyzeMove(themove):
    if themove.upper() in possibleTurns:
        return themove
    # This works but it switches the turn to player 1 even if its player 2 who makes a mistake.
    if themove.upper() not in possibleTurns:
        print("Invalid Move")
        main()
    # A used move will replace the old move so an X A1 will become O if O is chosen in error.
    if themove.upper() in movesUsed:
        print("That move was used!")
        main()

Answer 1

问题是，当您递归调用 main() 时，它总是在轮到玩家 1 时开始。

不是在输入无效时递归，而是使用 while 循环不断请求输入，直到输入有效。 analyzeMove 可以 return False 表示移动无效，循环再次询问。

另一个错误是 analyzeMove() 在检查移动是否已被使用之前检查移动是否在 possibleTurns 中。

此外，不要复制玩家 1 和 2 的所有代码，而是使用一个变量来指示轮到谁。

possibleTurns = ("A1","A2","A3","B1","B2","B3","C1","C2","C3")
movesUsed = []

def main():    
    players = ["X","O"]
    cur_player = 0
    while len(movesUsed) < 9:
        while True:
            turnp1 = input(f"Choose a move Player {cur_player+1}: ")
            print(f"Your move was: {turnp1}")
            validMove = analyzeMove(turnp1)
            if validMove:
                break
        move(validMove,players[cur_player])
        score()
        movesUsed.append(validMove)
        cur_player = 1 if cur_player == 0 else 0

def analyzeMove(themove):
    if themove.upper() in movesUsed:
        print("That move was used!")
        return False
    if themove.upper() in possibleTurns:
        return themove
    else:
        print("Invalid Move")
        return False

处理 tictactoe 的异常情况

handling outlier cases for tictactoe

python

tic-tac-toe