将排序序号显示为列表中的计数

Question

我有以下输入文件

system info com1 command set
system info com2 command set 
system command set1 information description test
system command 21-22 information description pass
system command T1-T2-T3 information description file
system command commonset information description info

和以下命令

awk '/system command/&&/information description/ { gsub("\"","") ; print ++ OFS") Command = " }' inputfile.txt

给我以下输出

1) Command = set1
2) Command = 21-22
3) Command = T1-T2-T3
4) Command = commonset

有没有办法让我的命令列表计数不是简单的数字而是排序序号并得到这样的输出

1st) Command = set1
2nd) Command = 21-22
3rd) Command = T1-T2-T3
4th) Command = commonset

Answer 1

没有获取该序数的内置函数。我们需要亲手编写这段代码：

awk 'function ordinal(i,   mod, str) {mod = i%10; str=i; if (i~/1[1-3]$/) str=str "th"; else if (mod==1) str=str "st"; else if (mod==2) str=str "nd"; else if (mod==3) str=str "rd"; else str=str "th"; return str;} /system command/&&/information description/ { gsub(/"/,"") ; print ordinal(++i) ") Command = " }' file

1st) Command = set1
2nd) Command = 21-22
3rd) Command = T1-T2-T3
4th) Command = commonset

扩展形式：

awk '
function ordinal(i,   mod, str) {
   mod = i%10
   str = i
   if (i~/1[1-3]$/)  # for numbers ending in 11, 12, 13
      str = str "th"
   else if (mod==1)
      str = str "st"
   else if (mod==2)
      str = str "nd"
   else if (mod==3)
      str = str "rd"
   else
      str = str "th"
   return str
}
/system command/&&/information description/ {
   gsub(/"/,"")
   print ordinal(++i) ") Command = " 
}' file

实现上述功能的另一种方法是：

function ordinal(num,   idx, sfxs) {
   split("st nd rd th",sfxs," ")
   idx = ( (num ~ /[123]$/) && (num !~ /1[123]$/) ? num % 10 : 4 )
   return num sfxs[idx]
}

将排序序号显示为列表中的计数

Show sort ordinal numbers as count in a list

awk

ordinals