如何将 dicts/nested 字典转换为列表字典

Question

这是原文

uid_coins = {'141632864': {'username': 'Guest130679138', 'coins': 0}, 
        '141632884': {'username': 'Guest130679156', 'coins': 39123441}, 
        '141632886': {'username': 'Guest130679158', 'coins': 44006638}}

我想得到什么

d = {'uid':[141632864, 141632884, 141632886], 
'username': ['Guest130679138', 'Guest130679156', 'Guest130679158'], 
'coins': [0, 39123441, 44006638]}

原始字典中的键代表uid。

这是我所做的：

uid = list(uid_coins.keys())
username = [u_data['username'] for u_data in uid_coins.values()]
coins = [[u_data['coins'] for u_data in uid_coins.values()]]

d = {"uid":uid, "username":username, "coins":coins}


dict((key,d[key]) for d in data for key in d)

但我更愿意寻找一种通用的方法，无需再次手动声明密钥即可实现，这样它就可以与原始数据中的新密钥一起使用。

Answer 1

尝试：

uid_coins = {
    "141632864": {"username": "Guest130679138", "coins": 0},
    "141632884": {"username": "Guest130679156", "coins": 39123441},
    "141632886": {"username": "Guest130679158", "coins": 44006638},
}

out = {}
for k, v in uid_coins.items():
    out.setdefault("uid", []).append(k)
    out.setdefault("username", []).append(v["username"])
    out.setdefault("coins", []).append(v["coins"])

print(out)

打印：

{'uid': ['141632864', '141632884', '141632886'], 
 'username': ['Guest130679138', 'Guest130679156', 'Guest130679158'], 
 'coins': [0, 39123441, 44006638]}

Answer 2

与@Andrej Kesely 相似的版本，但 defaultdict

from collections import defaultdict

uid_coins = {
    '141632864': {'username': 'Guest130679138', 'coins': 0}, 
    '141632884': {'username': 'Guest130679156', 'coins': 39123441}, 
    '141632886': {'username': 'Guest130679158', 'coins': 44006638}
}

d = defaultdict(list)
for key, value in uid_coins.items():
    d['uid'].append(key)
    d['username'].append(value['username'])
    d['coins'].append(value['coins'])

输出：

defaultdict(<class 'list'>, {'uid': ['141632864', '141632884', '141632886'], 'username': ['Guest130679138', 'Guest130679156', 'Guest130679158'], 'coins': [0, 39123441, 44006638]})

Answer 3

通用化（基于 Andrej Kesely 的原始版本）：

d = {}
for k, v in uid_coins.items():
    d.setdefault('uid', []).append(k)
    for i in v.keys():
        d.setdefault(i, []).append(v[i])

Answer 4

这就是您可以从给定字典中以所需格式（如问题所述）获取输出的方法。

d = {'uid': list(uid_coins.keys()), 'username': [i['username'] for i in list(uid_coins.values())], 'coins': [i['coins'] for i in list(uid_coins.values())]}

list(uid_coins.keys()) 将 return 您所有的 uid 作为列表。

[i['username'] for i in list(uid_coins.values())] 将 return 'username' 值作为列表。

[i['coins'] for i in list(uid_coins.values())] 将 return 'coins' 值作为列表。

如何将 dicts/nested 字典转换为列表字典

How do I convert dict of dicts/nested dicts into dict of list

python

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list

dictionary-comprehension