在特定条件下增加计数器（例如：仅当用户没有输入错误答案时）

Question

现在，此 jsfiddle 中的代码会生成数学问题，当用户输入正确答案时，correct 计数器会增加。当用户输入 wrong 答案时，错误计数器会上升。我需要帮助更进一步。如果用户输入了错误的答案，正确的计数器就不能为该问题递增。他们必须得到正确的答案才能转到下一个问题，但是当他们回答正确时，正确的计数器不会增加。他们做错的那个问题只有错误的计数器递增一次。

我有时会卡在弄清楚这种类型的逻辑中：

pseudo Code:
attempt = 0 //set originally to 0 since question was  attempted and answer was wrong

        if(answer is right && attempt 0){
            correct++
        }else if(answer is wrong){
            wrong++
            attempt = 1  //question was attempted and answer was wrong
            //this is where i get stuck. if i set attempt to 0 here it doesnt help
        }

Answer 1

已编辑：每题做错也只算一次。

代码可以写成：

    attempt = 0;

    if(answer is right){
      // First attempt is correct
      if (attempt === 0) {
        correct++
      }
      // go to next question, no matter the first try is correct or not.
      // set attempts back to 0, for a new question.
      attempt= 0;
    }else if(answer is wrong){
        // If we tried it, but wrong, then mark the answer wrong
        if (attempt === 0) {
           wrong++
        }
        attempt++
    }

然后看看你修改后的逻辑 jsfiddle

在特定条件下增加计数器（例如：仅当用户没有输入错误答案时）

increment a counter under certain condition (ex: only if user didn't input wrong answer)

javascript

logic

counter

decision-tree