如何使用 spring i18n 表单错误

Question

所以我无法将这些默认消息更改为我想要的消息。在所有 JSP 文件中，它们工作得很好，但我不能让它们在表单中工作。

这是我的用户控制器：

 @RequestMapping(path = "/user/profile", method = RequestMethod.POST)
    public ModelAndView userProfilePost(@ModelAttribute("userForm") @Valid UserForm userForm, BindingResult result) {
        if(result.hasErrors()){
            return userProfileGet(userForm);
        }
        User user = us.findByEmail(SecurityContextHolder.getContext().getAuthentication().getName());
        user = userHelper.update(userForm, us ,user);
        userForm = new UserForm();
        userForm.setName(user.getName());
        userForm.setEmail(user.getEmail());
       return userProfileGet(userForm);
    }

然后我们有我的 WebConfig：

    @Bean
    public LocalValidatorFactoryBean localValidatorFactoryBean() {
        LocalValidatorFactoryBean bean = new LocalValidatorFactoryBean();
        bean.setValidationMessageSource(messageSource());
        return bean;
    }

    @Bean
    public MessageSource messageSource()
    {
        final ReloadableResourceBundleMessageSource messageSource = new ReloadableResourceBundleMessageSource();
        messageSource.setBasenames("classpath:languages_i18n/messages", "classpath:languages_i18n/validation");
        messageSource.setDefaultEncoding(StandardCharsets.UTF_8.displayName());
        messageSource.setCacheSeconds(5);
        return messageSource;
    }

我的用户表单：

public class UserForm {
    @Email()
    private String email;
    @Size(max=100 , min=3)
    private String password;
    @Size(max=100 , min =3)
    private String name;

    public String getEmail() { return email; }
    public void setEmail(String email) { this.email = email; }

    public String getPassword() {
        return password;
    }
    public void setPassword(String password) {
        this.password = password;
    }

    public String getName() { return name; }
    public void setName(String name) { this.name = name; }
}

这里我也试过（当然没用哈哈）：

    @Email(message = "{Email.UserForm.email}")
    private String email;
    @Size(max=100 , min=3, message = "{Size.UserForm.password}")
    private String password;
    @Size(max=100 , min =3, message = "{Size.UserForm.name}")
    private String name;

这是我的 validation_en.properties:

Email.UserForm.email = Your e-mail format is not valid
Size.UserForm.password = Your password must have between {min} and {max} characters
Size.UserForm.name = Your name must have between {min} and {max} characters

我知道当我做对时，.properties 文件中的行应该是彩色的，但它们仍然是灰色的，所以很明显我没有正确到达它们。任何评论都会收到，提前谢谢。

Answer 1

参数为对象数组。

{0}为字段名，其他字段按字母顺序，先大后小。

所以应该是：

Size.UserForm.password = Your password must have between {2} and {1} characters
Size.UserForm.name = Your name must have between {2} and {1} characters

Answer 2

显然解决方案是表格的第一个字母应该小写，像这样（我不知道为什么）：

Size.userForm.password = Your password must have between {2} and {1} characters
Size.userForm.name = Your name must have between {2} and {1} characters

之后我们必须添加 Tung Phan 所说的也是正确的，因为参数是对象数组，所以 {min} 和 {max} 是错误的。

希望这对以后的任何人都有用。

如何使用 spring i18n 表单错误

How to i18n form errors with spring

java

spring

jsp

error-messaging