插入 RANK 作为列的值

Question

我是 sql 的超级新手，不知道是否可行，但是我想从以下 SELECT DISTINCT 输出中 select RANK 的值并将其插入到名为 Country.table 的第一列。

然后 select address_country 列并将其插入 table“国家/地区”的第二列，但我不知道该怎么做。我真的很感激任何帮助。谢谢！

INSERT INTO Country

SELECT country_code from
            (SELECT DISTINCT address_country,
            RANK() over (order by address_country asc) AS country_code      
            FROM CUSTOMER_INFO Where CUSTOMER_INFO.address_country is not NULL),

SELECT address_country from 
            (SELECT DISTINCT address_country,
            RANK() over (order by adr_country asc) AS country_code          
            FROM CUSTOMER_INFO
            Where CUSTOMER_INFO.address_country is not NULL);

Answer 1

如果您想 INSERT INTO ... SELECT，请使用：

INSERT INTO Country (address_country, country_code)
SELECT address_country, RANK() OVER (ORDER BY adr_country)
FROM CUSTOMER_INFO
WHERE CUSTOMER_INFO.address_country IS NOT NULL;

请注意，计算 RANK 将产生派生数据，或者可能会随着原始 CUSTOMER_INFO table 的变化而变化的数据。因此，您可能需要重新考虑最初导致您想要执行此插入操作的方法。

插入 RANK 作为列的值

Inserting RANK as value of a column

mysql

sql

rank

distinct-values

sql-insert