Gurobi 没有最小化 Objective 函数

Question

问题如下：

令 predict = [15, 15, 17, 16, 14, 15, 16, 14, 14, 22] 为数字列表。我想要一个数字序列 x = [x0,x2,x3,....,x9] 这样

|x[0] - predict[0]| + |x[1] - predict[1]| + ...+ |x[9]-predict[9]|

最低。约束是 |x[i]-x[i+1]| <= 1 for i = 0 to 9。我在jupyter notebook的python3中写了一段代码如下：


original = [16, 15, 16, 15, 15, 14, 14, 15, 15, 15]
predict = [17, 15, 17, 16, 14, 13, 15, 14, 16, 24]
varlen = len(original)

import gurobipy as gp
from gurobipy import GRB
model = gp.Model()
I = range(varlen) 

x = model.addVars(I, vtype = GRB.INTEGER, name = "x")
y = model.addVars(I, vtype = GRB.INTEGER, name = "y")  
z = model.addVars(I, vtype=GRB.INTEGER, name="z")

#Adding objective function sum of z[i] = sum|y[i]| = sum |x[i]-predict[i]|
model.setObjective(gp.quicksum(z[i] for i in I), GRB.MINIMIZE)

model.addConstrs(z[i] == gp.abs_(y[i]) for i in I)
model.addConstrs(y[i] == (x[i]-predict[i]) for i in I)

#constraint |x[i] - x[i+1]| <= diff
model.addConstrs(x[i]-x[i+1] <= diff for i in range(varlen-1))
model.addConstrs(x[i]-x[i+1] >= -diff for i in range(varlen-1))
model.params.outputflag = 0

model.optimize()
temp = model.x
out = [0]*len(x)
for i in range(len(out)):
    out[i] = int(temp[i])
print(out)
print(model.ObjVal)

输出： [17, 16, 17, 18, 19, 20, 21, 22, 23, 24]

36.0

但是 x = original = [16, 15, 16, 15, 15, 14, 14, 15, 15, 15] 满足所有约束并给出 ObjVal = 17 小于 36.0.

这意味着代码没有最小化给定的 objective 函数。我无法弄清楚代码有什么问题。我是 gurobi 的初学者，如果你们能提供帮助那就太好了。感谢任何解决方案。

Answer 1

注意addVars方法的签名：

model.addVars(*indexes, lb=0.0, ub=GRB.INFINITY, obj=0.0, vtype=GRB.CONTINUOUS, name="")

即每个变量的默认下限是 0。因此，我们有 y[i] == x[i] - predict[i] >= 0，这意味着 x[i] 不允许小于 predict[i]。

通过

删除变量的下限

x = model.addVars(I, lb=-1*GRB.INFINITY, vtype = GRB.INTEGER, name = "x")
y = model.addVars(I, lb=-1*GRB.INFINITY, vtype = GRB.INTEGER, name = "y")
z = model.addVars(I, lb=-1*GRB.INFINITY, vtype = GRB.INTEGER, name = "z")

您将获得 objective 值为 11 的解。

Gurobi 没有最小化 Objective 函数

Gurobi is not Minimizing the Objective function

python

optimization

operations-research

gurobi