你能解释一下为什么在下面的代码中出现编译时错误吗

Question

为什么我在下面给出的代码中出现错误....

#include <stdio.h>
    void foo(int*);
    int main()
    {
        int i = 10;
        foo((&i)++);(in this line error shows like this) //error: lvalue required as increment operand
    }
    void foo(int *p)
    {
        printf("%d\n", *p);
    }

Answer 1

来自Member access operators：

The address-of operator produces the non-lvalue address of its operand, suitable for initializing a pointer to the type of the operand.

并且来自 Increment/decrement operators：

The operand expr of both prefix and postfix increment or decrement must be a modifiable lvalue of integer type (including _Bool and enums), real floating type, or a pointer type.

简单地说，& 运算符没有为 ++ 运算符生成合适的对象。

你能解释一下为什么在下面的代码中出现编译时错误吗

can you explain why compile time error in the below code

c

pointers

function-pointers