如何根据 tkinter 菜单中的选定选项触发按钮？

Question

我有一个列表和 3 个路径。每条路径都指的是运行专门针对该国家/地区的应用程序。

country = ['Spain', 'United Kingdom', 'Malaysia']

path_spain = r"c:\data\FF\Desktop\PythonFolder\spain_software.py"
path_uk = r"c:\data\FF\Desktop\PythonFolder\uk_software.py"
path_malaysia = r"c:\data\FF\Desktop\PythonFolder\malaysia_software.py"

我创建的 Run button 需要根据我在 OptionMenu 中 select 的国家/地区触发这 3 个应用程序之一。所以如果我 select Malaysia 我想 Run button 到运行中的应用程序 path_malaysia。我正在努力解决这个问题。例如，如果我在 OptionMenu 中单击 Malaysia，我还希望将 Run button 更改为 Run application Malaysia。

这是我的代码：

import os
from tkinter import *
       
window = Tk()
window.title("Running Python Script") #Create window
window.geometry('550x300') #geo of the window

def run():
    os.system('python path_spain') 

#The run button (this button runs some other software)
run_button = Button(window, text="Run application.....", bg="blue", fg="white",command=run)
run_button.grid(column=0, row=2)

#These are the option menus
dd_country = StringVar(window)
dd_country.set(country [0]) #the first value
w = OptionMenu(window, dd_country, *country)
w.grid(row=0,column=1)

#These are the titles
l1 = Label(window,  text='Select Country', width=15 )  
l1.grid(row=0,column=0)

mainloop()

现在只有运行西班牙...

Answer 1

import os
from tkinter import *

owner = ['Spain', 'United Kingdom', 'Malaysia']

path_spain = r"c:\data\FF\Desktop\PythonFolder\spain_software.py"
path_uk = r"c:\data\FF\Desktop\PythonFolder\uk_software.py"
path_malaysia = r"c:\data\FF\Desktop\PythonFolder\malaysia_software.py"

window = Tk()
window.title("Running Python Script")  # Create window
window.geometry('550x300')  # geo of the window


def run():
    if dd_owner.get() == "Spain":
        print("spain")
        # os.system('python path_spain')
    elif dd_owner.get() == "United Kingdom":
        os.system('python path_uk')

    elif dd_owner.get() == "Malaysia":
        os.system('python path_malaysia')


def update_button(_):
    run_button.config(text="Run application {}".format(dd_owner.get()))


# The run button (this button runs some other software)


# These are the option menus
dd_owner = StringVar(window)
dd_owner.set(owner[0])  # the first value
w = OptionMenu(window, dd_owner, *owner, command=update_button)
# w.config()
w.grid(row=0, column=1)

run_button = Button(window, text="Run application {}".format(dd_owner.get()), bg="blue", fg="white",command=run)
run_button.grid(column=0, row=2)

# These are the titles
l1 = Label(window, text='Select Owner', width=15)
l1.grid(row=0, column=0)

mainloop()

这将解决您的问题

Answer 2

你可以试试这个：

def run():
    if dd_owner.get() == "Spain":
        os.system(f'python "{path_spain}"') #=== Run the file by formatting the path into the string
    elif dd_owner.get() == "United Kingdom":
        os.system(f'python "{path_uk}"')  #=== Run the file by formatting the path into the string
    
    elif dd_owner.get() == "Malaysia":
        os.system(f'python "{path_malaysia}"')  #=== Run the file by formatting the path into the string

还要更改按钮文本：

def change_text(*args):
    if dd_owner.get() == "Spain":
        
        run_button.config(text="Run Application Spain") #== Configure button
    elif dd_owner.get() == "United Kingdom":
        
        run_button.config(text="Run Application United Kingdom") #== Configure button
    elif dd_owner.get() == "Malaysia":
        
        run_button.config(text="Run Application Malaysia") #== Configure button

另外记得加上这段代码：

dd_owner.trace("w",change_text) #=== Trace the stringVar for changes.

更改按钮代码。

放在下面dd_owner.set(owner[0]) # the first value

综上，代码如下：

import os
from tkinter import *

owner = ['Spain', 'United Kingdom', 'Malaysia']

path_spain = "C:/data/FF/Desktop/PythonFolder/spain_software.py"
path_uk = "C:/data/FF/Desktop/PythonFolder/uk_software.py"
path_malaysia = "C:/data/FF/Desktop/PythonFolder/malaysia_software.py"

window = Tk()
window.title("Running Python Script")  # Create window
window.geometry('550x300')  # geo of the window


def run():
    if dd_owner.get() == "Spain":
        os.system(f'python "{path_spain}"')
        run_button.config(text="Run Application Spain")
    elif dd_owner.get() == "United Kingdom":
        os.system(f'python "{path_uk}"')
        run_button.config(text="Run Application United Kingdom")
    elif dd_owner.get() == "Malaysia":
        os.system(f'python "{path_malaysia}"')
        run_button.config(text="Run Application Malaysia")

def change_text(*args):
    if dd_owner.get() == "Spain":
        
        run_button.config(text="Run Application Spain")
    elif dd_owner.get() == "United Kingdom":
        
        run_button.config(text="Run Application United Kingdom")
    elif dd_owner.get() == "Malaysia":
        
        run_button.config(text="Run Application Malaysia")

# The run button (this button runs some other software)
dd_owner = StringVar(window)
dd_owner.set(owner[0])  # the first value

run_button = Button(window, text=f"Run application {dd_owner.get()}", bg="blue", fg="white", command=run)
run_button.grid(column=0, row=2)

# These are the option menus
w = OptionMenu(window, dd_owner, *owner)
dd_owner.trace("w",change_text)
w.grid(row=0, column=1)

# These are the titles
l1 = Label(window, text='Select Owner', width=15)
l1.grid(row=0, column=0)

window.mainloop()

如何根据 tkinter 菜单中的选定选项触发按钮？

How to triger a button based on the selected option in menu in tkinkter?

python

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button

tkinter.optionmenu