XSLT - select 个具有相同属性但稍后忽略相同 element/same 属性的连续元素

Question

我有这个XML:

  <doc>
    <paragraph>AAA</paragraph>
    <paragraph stylename="numbered" num="1">BBB</paragraph>
    <paragraph stylename="numbered" num="2">CCC</paragraph>
    <paragraph>DDD</paragraph>
    <paragraph>EEE</paragraph>
    <paragraph stylename="numbered" num="1">FFF</paragraph>
    <paragraph stylename="numbered" num="2">GGG</paragraph>
    <paragraph stylename="numbered" num="3">HHHh</paragraph>
    <paragraph>III</paragraph>
  </doc>

我需要统计连续段的总数[@stylename='numbered']并输出：

<paragraph>AAA</paragraph>
<paragraph count="1" totalnums="2">BBBa</paragraph>
<paragraph count="2" totalnums="2">CCC</paragraph>
<paragraph>DDD</paragraph>
<paragraph>EEE</paragraph>
<paragraph count="1" totalnums="3">FFF</paragraph>
<paragraph count="2" totalnums="3">GGG</paragraph>
<paragraph count="3" totalnums="3">HHH</paragraph>
<paragraph>III</paragraph>

我不知道如何输出连续@stylename="numbered" 的@count 或总数(@totalnums)。

目前，我得到了整个文件中的段落总数/@stylename="numbered"。

任何指针 and/or 代码将不胜感激。（首选 XSLT-1.0 解决方案，尽管 2.0 也可能实现）

Answer 1

这在 XSLT 2.0 中使用 xsl:for-each-group 和 group-adjacent 很容易做到。要在 XSLT 1.0 中实现相同的目标更加困难：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>

<xsl:key name="k1" match="paragraph[@stylename='numbered']" use="generate-id(preceding-sibling::paragraph[not(@stylename='numbered')][1])" />

<!-- identity transform -->
<xsl:template match="@*|node()">
    <xsl:copy>
        <xsl:apply-templates select="@*|node()"/>
    </xsl:copy>
</xsl:template>

<xsl:template match="paragraph[@stylename='numbered']">
    <xsl:variable name="grp" select="key('k1', generate-id(preceding-sibling::paragraph[not(@stylename='numbered')][1]))" />
    <!-- if this is the first one in the group -->
    <xsl:if test="generate-id()=generate-id($grp[1])">
        <xsl:for-each select="$grp">
            <paragraph count="{position()}" totalnums="{last()}">
                <xsl:value-of select="."/>
            </paragraph>            
        </xsl:for-each>
    </xsl:if>
</xsl:template>

</xsl:stylesheet>

应用于您的示例输入，这将 return:

结果

<doc>
  <paragraph>AAA</paragraph>
  <paragraph count="1" totalnums="2">BBB</paragraph>
  <paragraph count="2" totalnums="2">CCC</paragraph>
  <paragraph>DDD</paragraph>
  <paragraph>EEE</paragraph>
  <paragraph count="1" totalnums="3">FFF</paragraph>
  <paragraph count="2" totalnums="3">GGG</paragraph>
  <paragraph count="3" totalnums="3">HHHh</paragraph>
  <paragraph>III</paragraph>
</doc>

这与您问题中显示的结果不同，但我相信它是正确的。

XSLT - select 个具有相同属性但稍后忽略相同 element/same 属性的连续元素

XSLT - select consecutive elements with the same attribute but ignore later same element/same attribute

xslt-1.0