将字符向量转换为具有指定列数的 data.frame

Question

我有一个数据向量，其中每第 4 行开始一个新观察。我需要旋转数据，使前四个值成为第一行，接下来的四个值成为第二行，依此类推。

这是一个简化的例子...

给定以下数据：

a <- rep(c("a", "b", "c", "d"), 3)

期望的输出是：

  A_lab B_lab C_lab D_lab
1     a     b     c     d
2     a     b     c     d
3     a     b     c     d

Answer 1

这是一个使用 dplyr 和 tidyverse 的选项

require(tidyverse)
a <- rep(c("a", "b", "c", "d"), 3)

labs = rep(c("A_lab", "B_lab", "C_lab", "D_lab"), 3)
obs_id <- rep(1:3, each=length(unique(a)))


tibble(vals = a, labs = labs,  obs_id = obs_id) %>%
  pivot_wider(obs_id, values_from = vals, names_from = labs)


# A tibble: 3 x 5
#  obs_id A_lab B_lab C_lab D_lab
#   <int> <chr> <chr> <chr> <chr>
#1      1 a     b     c     d    
#2      2 a     b     c     d    
#3      3 a     b     c     d

Answer 2

如果你想要一个矩阵，只需调用：

matrix(a, ncol=4, byrow=TRUE)

     [,1] [,2] [,3] [,4]
[1,] "a"  "b"  "c"  "d" 
[2,] "a"  "b"  "c"  "d" 
[3,] "a"  "b"  "c"  "d"

对于 data.frame，结果通过管道传输到 data.frame:

data.frame(matrix(a, ncol=4, byrow=TRUE))

  X1 X2 X3 X4
1  a  b  c  d
2  a  b  c  d
3  a  b  c  d

Answer 3

a <- rep(c("a", "b", "c", "d"), 3)

library(tidyverse)
a %>% as.data.frame() %>% setNames('V') %>%
  mutate(dummy = (( row_number() -1) %% 4)+1) %>%
  pivot_wider(names_from = dummy, values_from = V, values_fn = list) %>%
  unnest(everything())
#> # A tibble: 3 x 4
#>   `1`   `2`   `3`   `4`  
#>   <chr> <chr> <chr> <chr>
#> 1 a     b     c     d    
#> 2 a     b     c     d    
#> 3 a     b     c     d

^{由 reprex package (v2.0.0)}

创建于 2021-06-01

将字符向量转换为具有指定列数的 data.frame

Pivot a character vector to a data.frame with specified number of columns

r

data-munging