如何使用数组中的所有值获取记录

Question

数组中的值是动态的，可多可少。如果任何值是真的，我就会得到结果。但如果数组中的所有值都为真，我想获取记录记录。 重要：数组中的值是动态的

 SELECT J.ID , J.U_POST_ID,
                    J.TITLE,J.CREATION_DATE,J.STATUS,
                    R.FIRST_NAME, R.LAST_NAME,R.CLINICAL_CLINIC_NAME,
                    J.REQUIREMENT,J.STATE,J.CITY,J.DESCRIPTION,J.CALL_DUR,J.USER_ID
                    FROM df_job_meta M JOIN df_job_post J ON 
                    M.JOB_ID = J.ID JOIN df_register_users R ON 
                    R.ID = J.USER_ID WHERE J.STATUS='ACTIVE'  AND R.OCCUPATION !='student' AND  M.VALUE IN ('Fresher','Full Time') group  BY J.ID

table:df_job_meta

--------------------------------------
|JOB_ID  | META_KEY    | VALUE       | 
-------------------------------------|
| 91     | experience  |Fresher      |
| 91     | work_hour   |Full Time    |
| 91     | pay_scale   |Sharing      |
| 91     | gender      |Female       |
| 92     | experience  |3 to 5 Years |
| 92     | work_hour   |Part Time    |  
---------------------------------------

Answer 1

如果您使用上述查询，请使用此方法：

$q = mysql_query("SELECT J.ID , J.U_POST_ID,
                J.TITLE,J.CREATION_DATE,J.STATUS,
                R.FIRST_NAME, R.LAST_NAME,R.CLINICAL_CLINIC_NAME,
                J.REQUIREMENT,J.STATE,J.CITY,J.DESCRIPTION,J.CALL_DUR,J.USER_ID
                FROM df_job_meta M JOIN df_job_post J ON 
                M.JOB_ID = J.ID JOIN df_register_users R ON 
                R.ID = J.USER_ID WHERE J.STATUS='ACTIVE'  AND R.OCCUPATION !='student' AND  M.VALUE IN ('Fresher','Full Time') group  BY J.ID");

while($r=mysql_fetch_array($q))
{
   echo $r['JOB_ID'].$r['META_KEY'].$r['VALUE'];
}

Answer 2

我认为您需要的是将返回的记录数与 IN 子句中的条件数相匹配。那样的话，基本上就用

SELECT M.JOB_ID
FROM df_job_meta M
WHERE M.VALUE IN ('Fresher','Full Time')
GROUP BY M.JOB_ID
HAVING COUNT(DISTINCT M.VALUE) = 2

数组中有 2 个值，因此计数必须等于 2。如果您有 N 个值，那么查询应该类似于

SELECT M.JOB_ID
FROM df_job_meta M
WHERE M.VALUE IN (1,2,...,N)
GROUP BY M.JOB_ID
HAVING COUNT(DISTINCT M.VALUE) = N

您可以使用 php 实现该部分，因为您有一个动态数组。当然，您需要将该查询与上面的主查询结合起来。

编辑

如果每个 JOB_ID 没有相同 VALUE 的重复行，您可以简单地执行 COUNT(M.VALUE) 而不是 COUNT(DISTINCT M.VALUE)

编辑 2

我还包含了完整的 sql 声明。 (可能有错误，因为没有提供ddl)

SELECT J.ID , J.U_POST_ID,
J.TITLE,J.CREATION_DATE,J.STATUS,
R.FIRST_NAME, R.LAST_NAME,R.CLINICAL_CLINIC_NAME,
J.REQUIREMENT,J.STATE,J.CITY,J.DESCRIPTION,J.CALL_DUR,J.USER_ID
FROM df_job_post J JOIN df_register_users R ON R.ID = J.USER_ID 
WHERE J.STATUS='ACTIVE'  AND R.OCCUPATION !='student' 
AND  J.ID IN 
(
    SELECT M.JOB_ID
    FROM df_job_meta M
    WHERE M.VALUE IN ('Fresher','Full Time')
    GROUP BY M.JOB_ID
    HAVING COUNT(DISTINCT M.VALUE) = 2
)

编辑 3

精确匹配可以把query改成这样

SELECT J.ID , J.U_POST_ID,
J.TITLE,J.CREATION_DATE,J.STATUS,
R.FIRST_NAME, R.LAST_NAME,R.CLINICAL_CLINIC_NAME,
J.REQUIREMENT,J.STATE,J.CITY,J.DESCRIPTION,J.CALL_DUR,J.USER_ID
FROM df_job_post J JOIN df_register_users R ON R.ID = J.USER_ID 
WHERE J.STATUS='ACTIVE'  AND R.OCCUPATION !='student' 
AND  J.ID IN 
(
    SELECT M.JOB_ID
    FROM df_job_meta M
    WHERE M.VALUE IN ('Fresher','Full Time')
    GROUP BY M.JOB_ID
    HAVING COUNT(DISTINCT M.VALUE) = 2 AND COUNT(DISTINCT M.VALUE) = (SELECT COUNT( * ) FROM df_job_meta WHERE JOB_ID = M.JOB_ID)
)

你基本上是在检查返回的行数是否等于实际计数：

COUNT(DISTINCT M.VALUE) = (SELECT COUNT( * ) FROM df_job_meta WHERE JOB_ID = M.JOB_ID)

如何使用数组中的所有值获取记录

How to fetch record using all values in array

php

mysql

pdo