通过 HttpContext 发送 EPPLus Excel 文件

Sending EPPLus Excel file via HttpContext

我正在为我的 .NET Core 3.1 应用程序使用 EPPLus 库;目前我正在尝试实现一个简单的 Export 函数,它根据给定的数据生成 sheet 并立即将其下载到用户 PC。

我有以下内容:

    public void Export(ProductionLine productionLine, HttpContext context)
    {
        using (var package = new ExcelPackage())
        {
            var ws = package.Workbook.Worksheets.Add("MySheet");
            ws.Cells["A1"].Value = "This is cell A1";


            context.Response.ContentType = "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet";
            context.Response.Headers.Add(
                          "content-disposition",
                          string.Format("attachment;  filename={0}", "MySheet.xlsx"));
            context.Response.SendFileAsync(package);

        }
    }

HttpContext 是通过一个简单地调用 HttpContext 控制器基础的控制器给出的。 HttpContext 基于 Microsoft.AspNetCore.Http

我目前遇到的错误是 cannot convert from 'OfficeOpenXml.ExcelPackage' to 'Microsoft.Extensions.FileProviders.IFileInfo' 合乎逻辑的,但我认为将文件更改为 IFileInfo 是不可能的。

是否有另一种通过 HttpContextResponse 发送 EPPlus 文件的方法?

折腾了一下,好像还是用return File()功能更方便。我重做了 Export 函数,如下所示:

    public object Export(ProductionLine productionLine, HttpContext context)
    {

        ExcelPackage.LicenseContext = LicenseContext.NonCommercial;

        FileInfo fileName = new FileInfo("ExcellData.xlsx");
            using (var package = new OfficeOpenXml.ExcelPackage(fileName))
            {
            var ws = package.Workbook.Worksheets.Add("MySheet");
            ws.Cells["A1"].Value = "This is cell A1";

            MemoryStream result = new MemoryStream();
            result.Position = 0; 
            
            package.SaveAs(result);

            return result;
    }

我的控制器是这样的:

    public IActionResult ExportCSV([FromQuery] string Orderno)
    {
        try
        {
            ProductionLine prodLine = _Prodline_Service.GetAllByOrderno(Orderno);
            MemoryStream result = (MemoryStream)_ExcelExportService.Export(prodLine, HttpContext);
            // Set memorystream position; if we don't it'll fail
            result.Position = 0;

            return File(result, "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet");
        } catch(Exception e)
        {
            Console.WriteLine(e);
            return null;
        }
    }