打印字典列表中的单独元素
Printing separate elements in lists in dictionaries
我在尝试打印字典列表中的每个元素以及字典中的其他项目时遇到问题。
#dictionaries
bill = {
"name": "Bill",
"job": "Policeman",
"hobbies": ["rugby","music","mischief"],
}
jill = {
"name": "Jill",
"job": "Lawyer",
"hobbies": ["driving","clubbing","basketball"],
}
will = {
"name": "Will",
"job": "Builder",
"hobbies": ["football","cooking","beatboxing"],
}
#list of citizens
citizens = [bill,jill,will]
#print keys with their values for each citizen
def citizen_info(citizens):
for citizen in citizens:
for item in citizen:
print ("%s: " + str(citizen[item])) % (item)
print ""
#Calling citizen_info
citizen_info(citizens)
如您所见,我试图打印每个字典中的所有项目,但是当我尝试打印列表中的单独元素时,它看起来像这样。
job: Policeman
name: Bill
hobbies: ['rugby', 'music', 'mischief']
job: Lawyer
name: Jill
hobbies: ['driving', 'clubbing', 'basketball']
job: Builder
name: Will
hobbies: ['football', 'cooking', 'beatboxing']
当我真正喜欢看起来像这样的时候:
hobbies: rugby music mischief
用谷歌搜索这个问题并在这个网站上搜索,我可以找到解决这个问题的解决方案,但如果字典中有另一个不是列表的项目,我就不起作用。
只需分别循环遍历爱好键:
#print keys with their values for each citizen
def citizen_info(citizens):
for citizen in citizens:
for item in citizen:
if item != "hobbies":
print(("%s: " + str(citizen[item])) % (item))
else:
print("hobbies", end="")
for hobby in citizen[item]:
print(hobby, end="")
print("")
print("")
您可以简单地使用一个三元条件,它会生成由空格连接的字符串,如果值是 list
类型,否则是简单字符串。
def citizen_info(citizens):
for citizen in citizens:
for item in citizen:
print ("%s: " + str(" ".join(citizen[item])) if isinstance(citizen[item], list) else "%s: " + str(citizen[item])) % (item)
print ""
def citizen_info(citizens):
for citizen in citizens:
for item in citizen:
if type(citizen[item]) is list :
print ("%s: " + " ".join(citizen[item])) % (item)
else :
print ("%s: " + str(citizen[item])) % (item)
print ""
或
def citizen_info2(citizens):
for citizen in citizens:
for item in citizen:
if item == "hobbies" :
print ("%s: " + " ".join(citizen[item])) % (item)
else :
print ("%s: " + str(citizen[item])) % (item)
print ""
如果你有一个列表 a = ['1', '2', '3'] 并且想连接里面的字符串:
" ".join(a)
", ".join(a)
看看这是否适合你:
def citizen_info(citizens):
for citizen in citizens: # loop through the citizens
for key, value in citizen.items(): # get keys and values
if type(value) is list: # test if the value is a list
value = " ".join(value) # join the list into a string
print("{}: {}".format(key, value)) # print however you want
def citizen_info(citizens):
for citizen in citizens:
for item in citizen:
if item != 'hobbies':
print ('{}: {}'.format(item, citizen[item]) # new style string formatting, much easier to read imo
else:
print ('{}: {}'.format(item, ' '.join(citizen[item]))
print ""
使用新样式的字符串格式并以不同方式处理 hobbies
键。
我在尝试打印字典列表中的每个元素以及字典中的其他项目时遇到问题。
#dictionaries
bill = {
"name": "Bill",
"job": "Policeman",
"hobbies": ["rugby","music","mischief"],
}
jill = {
"name": "Jill",
"job": "Lawyer",
"hobbies": ["driving","clubbing","basketball"],
}
will = {
"name": "Will",
"job": "Builder",
"hobbies": ["football","cooking","beatboxing"],
}
#list of citizens
citizens = [bill,jill,will]
#print keys with their values for each citizen
def citizen_info(citizens):
for citizen in citizens:
for item in citizen:
print ("%s: " + str(citizen[item])) % (item)
print ""
#Calling citizen_info
citizen_info(citizens)
如您所见,我试图打印每个字典中的所有项目,但是当我尝试打印列表中的单独元素时,它看起来像这样。
job: Policeman
name: Bill
hobbies: ['rugby', 'music', 'mischief']
job: Lawyer
name: Jill
hobbies: ['driving', 'clubbing', 'basketball']
job: Builder
name: Will
hobbies: ['football', 'cooking', 'beatboxing']
当我真正喜欢看起来像这样的时候:
hobbies: rugby music mischief
用谷歌搜索这个问题并在这个网站上搜索,我可以找到解决这个问题的解决方案,但如果字典中有另一个不是列表的项目,我就不起作用。
只需分别循环遍历爱好键:
#print keys with their values for each citizen
def citizen_info(citizens):
for citizen in citizens:
for item in citizen:
if item != "hobbies":
print(("%s: " + str(citizen[item])) % (item))
else:
print("hobbies", end="")
for hobby in citizen[item]:
print(hobby, end="")
print("")
print("")
您可以简单地使用一个三元条件,它会生成由空格连接的字符串,如果值是 list
类型,否则是简单字符串。
def citizen_info(citizens):
for citizen in citizens:
for item in citizen:
print ("%s: " + str(" ".join(citizen[item])) if isinstance(citizen[item], list) else "%s: " + str(citizen[item])) % (item)
print ""
def citizen_info(citizens):
for citizen in citizens:
for item in citizen:
if type(citizen[item]) is list :
print ("%s: " + " ".join(citizen[item])) % (item)
else :
print ("%s: " + str(citizen[item])) % (item)
print ""
或
def citizen_info2(citizens):
for citizen in citizens:
for item in citizen:
if item == "hobbies" :
print ("%s: " + " ".join(citizen[item])) % (item)
else :
print ("%s: " + str(citizen[item])) % (item)
print ""
如果你有一个列表 a = ['1', '2', '3'] 并且想连接里面的字符串:
" ".join(a)
", ".join(a)
看看这是否适合你:
def citizen_info(citizens):
for citizen in citizens: # loop through the citizens
for key, value in citizen.items(): # get keys and values
if type(value) is list: # test if the value is a list
value = " ".join(value) # join the list into a string
print("{}: {}".format(key, value)) # print however you want
def citizen_info(citizens):
for citizen in citizens:
for item in citizen:
if item != 'hobbies':
print ('{}: {}'.format(item, citizen[item]) # new style string formatting, much easier to read imo
else:
print ('{}: {}'.format(item, ' '.join(citizen[item]))
print ""
使用新样式的字符串格式并以不同方式处理 hobbies
键。