从 ant 目标替换多行 xml 文件

Question

我有一个 web.xml 大约有 10 个 servlet，这些 servlet 定义了一些基本配置，如下所示：

    <servlet>
    <servlet-name>dummyServlet</servlet-name>
    <servlet-class>com.abc.Servlet</servlet-class>
    <init-param>
        <param-name>target</param-name>
        <param-value>foo.com</param-value>
    </init-param>
    <init-param>
        <param-name>log</param-name>
        <param-value>true</param-value>
    </init-param>
</servlet>

<servlet-mapping>
    <servlet-name>dummyServlet</servlet-name>
    <url-pattern>/*</url-pattern>
</servlet-mapping>

        <servlet>
    <servlet-name>dummyServlet2</servlet-name>
    <servlet-class>com.abc.Servlet2</servlet-class>
    <init-param>
        <param-name>target</param-name>
        <param-value>foo.com</param-value>
    </init-param>
    <init-param>
        <param-name>log</param-name>
        <param-value>true</param-value>
    </init-param>
</servlet>

<servlet-mapping>
    <servlet-name>dummyServlet2</servlet-name>
    <url-pattern>/dummy</url-pattern>
</servlet-mapping>

        <servlet>
    <servlet-name>actualServlet</servlet-name>
    <servlet-class>com.abc.ActualServlet</servlet-class>
    <init-param>
        <param-name>target</param-name>
        <param-value>foo.com</param-value>
    </init-param>
    <init-param>
        <param-name>log</param-name>
        <param-value>true</param-value>
    </init-param>
</servlet>

<servlet-mapping>
    <servlet-name>dummyServlet</servlet-name>
    <url-pattern>/actual</url-pattern>
</servlet-mapping>

现在，根据某些条件，我需要从我的 ant 目标中删除两个虚拟 servlet 及其映射，但需要保留实际 servlet 及其映射。有人可以建议 best/easy 的方法吗？我应该使用 ant <replace> 还是 xmltask 或其他一些功能？替换整个 web.xml 不是一个选项。

Answer 1

我冒昧地在提供的 XML 中添加了一个根元素以使其格式正确。

请通过 XSLT 尝试以下解决方案。

XSLT 使用所谓的身份转换 模式。

您需要为您的真实 XML 修改两个模板：并提供要删除的虚拟 Servlet 列表。

虚拟 Servlet 之外的所有其他内容都将保持不变。

请记住 XML 区分大小写，包括实际值。

输入XML

<root>
    <servlet>
        <servlet-name>dummyServlet</servlet-name>
        <servlet-class>com.abc.Servlet</servlet-class>
        <init-param>
            <param-name>target</param-name>
            <param-value>foo.com</param-value>
        </init-param>
        <init-param>
            <param-name>log</param-name>
            <param-value>true</param-value>
        </init-param>
    </servlet>
    <servlet-mapping>
        <servlet-name>dummyServlet</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>
    <servlet>
        <servlet-name>dummyServlet2</servlet-name>
        <servlet-class>com.abc.Servlet2</servlet-class>
        <init-param>
            <param-name>target</param-name>
            <param-value>foo.com</param-value>
        </init-param>
        <init-param>
            <param-name>log</param-name>
            <param-value>true</param-value>
        </init-param>
    </servlet>
    <servlet-mapping>
        <servlet-name>dummyServlet2</servlet-name>
        <url-pattern>/dummy</url-pattern>
    </servlet-mapping>
    <servlet>
        <servlet-name>actualServlet</servlet-name>
        <servlet-class>com.abc.ActualServlet</servlet-class>
        <init-param>
            <param-name>target</param-name>
            <param-value>foo.com</param-value>
        </init-param>
        <init-param>
            <param-name>log</param-name>
            <param-value>true</param-value>
        </init-param>
    </servlet>
    <servlet-mapping>
        <servlet-name>dummyServlet</servlet-name>
        <url-pattern>/actual</url-pattern>
    </servlet-mapping>
</root>

XSLT

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml" encoding="utf-8" indent="yes" omit-xml-declaration="yes"/>
    <xsl:strip-space elements="*"/>

    <xsl:template match="@*|node()">
        <xsl:copy>
            <xsl:apply-templates select="@*|node()"/>
        </xsl:copy>
    </xsl:template>

    <xsl:template match="servlet[servlet-name=('dummyServlet','dummyServlet2')]">
    </xsl:template>
        <xsl:template match="servlet-mapping[servlet-name=('dummyServlet','dummyServlet2')]">
    </xsl:template>
</xsl:stylesheet>

输出XML

<root>
  <servlet>
    <servlet-name>actualServlet</servlet-name>
    <servlet-class>com.abc.ActualServlet</servlet-class>
    <init-param>
      <param-name>target</param-name>
      <param-value>foo.com</param-value>
    </init-param>
    <init-param>
      <param-name>log</param-name>
      <param-value>true</param-value>
    </init-param>
  </servlet>
</root>

从 ant 目标替换多行 xml 文件

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