如何在 python 中打印 S3 密钥名称

Question

我已经为新对象的所有放置添加了 S3 触发器并调用了 AWS Lambda。

我的 Lambda 是用 Python 3.8 编写的，用于解析关键对象和文件并获取文件名。

import urllib.parse
import boto3

print('Loading function')

s3 = boto3.client('s3')


def lambda_handler(event, context):
    #print("Received event: " + json.dumps(event, indent=2))

    # Get the object from the event and show its content type
    bucket = event['Records'][0]['s3']['bucket']['name']
    key = urllib.parse.unquote_plus(event['Records'][0]['s3']['object']['key'], encoding='utf-8')
    try:
        print(key)

一旦我上传mys3bucket/jsonfiles/2021/05/31/file.json

我的代码打印 jsonfiles/2021/05/31/file.json, 我想打印的是。

key1 as 2021/05/31/, omitting the jsonfiles prefix
and
key2 as file.json, printing just the file name.

我的代码应该是什么样的？

Answer 1

一旦你得到 key 做一些字符串解析并从中获取你需要的数据，

>>> s = "mys3bucket/jsonfiles/2021/05/31/file.json"
>>> s.split("jsonfiles/")
['mys3bucket/', '2021/05/31/file.json']
>>> req = s.split("jsonfiles/")[1]
>>> ind = req.rfind('/')
>>> req[:ind]
'2021/05/31'
>>> req[ind + 1:]
'file.json'

如何在 python 中打印 S3 密钥名称

How to print the S3 key name in python

python

json

amazon-s3

aws-lambda

python-3.8