UIKit SearchBar 在 textDidChange 中过滤两个数组
UIKit SearchBar Filter Two Arrays in textDidChange
我有两个初始化和未初始化的数组如下:
var colours: [String] = ["Blue", "Red", "Green", "Yellow"]
var numbers: [Int] = [11, 12, 13, 14]
var coloursFiltered: [String]?
var numbersFiltered: [Int]?
在我的搜索栏中,我只能过滤 textDidChange
函数中的一个数组,如下所示:
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
coloursFiltered = colours.filter({ item -> Bool in
if searchText.isEmpty { return true }
return item.lowercased().contains(searchText.lowercased())
})
tableView.reloadData()
}
/* Later in the Code */
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return coloursFiltered!.count
}
我还需要过滤 numbers
数组以匹配过滤后的 colours
数组的相应索引。我不能这样做,因为我无法访问 colours.filter
函数中的当前索引。这是为了达到以下目的:
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
self.tableView.register(UINib.init(nibName: "ItemTableViewCell", bundle: nil), forCellReuseIdentifier: "ItemTableViewCell")
let cell = self.tableView.dequeueReusableCell(withIdentifier: "ItemTableViewCell", for: indexPath) as! ItemTableViewCell
cell.name.text = "\(coloursFiltered![indexPath.row])"
cell.code.text = ""\(numbersFiltered![indexPath.row])" // I need this to work
return cell
}
有没有办法使用相同的字符串过滤两个数组?
你最好有个模型
struct Item {
let color:String
let number:Int
}
然后
var all = [Item(color:"Blue",number:11),.....]
var coloursFiltered = [Item]()
然后过滤它
coloursFiltered = all.filter({ item -> Bool in
if searchText.isEmpty { return true }
return item.color.lowercased().contains(searchText.lowercased())
})
tableView.reloadData()
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return coloursFiltered.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
self.tableView.register(UINib(nibName: "ItemTableViewCell", bundle: nil), forCellReuseIdentifier: "ItemTableViewCell")
let cell = self.tableView.dequeueReusableCell(withIdentifier: "ItemTableViewCell", for: indexPath) as! ItemTableViewCell
let item = coloursFiltered[indexPath.row]
cell.name.text = item.color
cell.code.text = "\(item.number)"
return cell
}
我尝试了 and it is working and very helpful. Here is a similar approach to the solution that I found in another question inspired by @Aju Antony 的答案。
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
let result = zip(colours, numbers).filter { name, code in
name.lowercased().contains(searchText.lowercased()) ||
String(code).contains(searchText.lowercased())
}
let filteredNames = result.map({ [=10=].0 })
let filteredCodes = result.map({ [=10=].1 })
self.coloursFiltered = filteredNames
self.numberseFiltered = filteredCodes
tableView.reloadData()
}
我有两个初始化和未初始化的数组如下:
var colours: [String] = ["Blue", "Red", "Green", "Yellow"]
var numbers: [Int] = [11, 12, 13, 14]
var coloursFiltered: [String]?
var numbersFiltered: [Int]?
在我的搜索栏中,我只能过滤 textDidChange
函数中的一个数组,如下所示:
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
coloursFiltered = colours.filter({ item -> Bool in
if searchText.isEmpty { return true }
return item.lowercased().contains(searchText.lowercased())
})
tableView.reloadData()
}
/* Later in the Code */
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return coloursFiltered!.count
}
我还需要过滤 numbers
数组以匹配过滤后的 colours
数组的相应索引。我不能这样做,因为我无法访问 colours.filter
函数中的当前索引。这是为了达到以下目的:
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
self.tableView.register(UINib.init(nibName: "ItemTableViewCell", bundle: nil), forCellReuseIdentifier: "ItemTableViewCell")
let cell = self.tableView.dequeueReusableCell(withIdentifier: "ItemTableViewCell", for: indexPath) as! ItemTableViewCell
cell.name.text = "\(coloursFiltered![indexPath.row])"
cell.code.text = ""\(numbersFiltered![indexPath.row])" // I need this to work
return cell
}
有没有办法使用相同的字符串过滤两个数组?
你最好有个模型
struct Item {
let color:String
let number:Int
}
然后
var all = [Item(color:"Blue",number:11),.....]
var coloursFiltered = [Item]()
然后过滤它
coloursFiltered = all.filter({ item -> Bool in
if searchText.isEmpty { return true }
return item.color.lowercased().contains(searchText.lowercased())
})
tableView.reloadData()
func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return coloursFiltered.count
}
func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
self.tableView.register(UINib(nibName: "ItemTableViewCell", bundle: nil), forCellReuseIdentifier: "ItemTableViewCell")
let cell = self.tableView.dequeueReusableCell(withIdentifier: "ItemTableViewCell", for: indexPath) as! ItemTableViewCell
let item = coloursFiltered[indexPath.row]
cell.name.text = item.color
cell.code.text = "\(item.number)"
return cell
}
我尝试了
func searchBar(_ searchBar: UISearchBar, textDidChange searchText: String) {
let result = zip(colours, numbers).filter { name, code in
name.lowercased().contains(searchText.lowercased()) ||
String(code).contains(searchText.lowercased())
}
let filteredNames = result.map({ [=10=].0 })
let filteredCodes = result.map({ [=10=].1 })
self.coloursFiltered = filteredNames
self.numberseFiltered = filteredCodes
tableView.reloadData()
}