还有其他简单的方法可以更改我的原始 JavaScript 代码吗?
Is there any other simple way to change my vanilla JavaScript code?
有没有办法让我的代码更简单?
仅供参考,我是初学者,我只学习了 JavaScript 一周。
谢谢!
let array = [1,2,4,591,392,391,2,5,10,2,1,1,1,20,20];
// from above to [[1, 1, 1, 1], [2, 2, 2], 4, 5, 10, [20, 20], 391, 392, 591]
const answer = (arr) => {
arr.sort((a, b) => {
return a - b;
});
let counter = 0;
arr.forEach((num, i) => {
if (arr[i] === arr[i+1]) {
counter++;
} else if (arr[i] !== arr[i + 1] && arr[i] === arr[i-1]) {
arr[i-counter] = arr.slice(i-counter, i + 1);
counter = 0;
}
});
arr.forEach((num, i) => {
while (arr[i][0] && arr[i][0] === arr[i + 1]) {
arr.splice(i + 1, 1);
}
});
return arr;
}
const newArray = answer(array);
console.log(newArray);
你可以简单点,先排序再分组。
let array = [1, 2, 4, 591, 392, 391, 2, 5, 10, 2, 1, 1, 1, 20, 20],
last = null;
const result = array
.sort((a, b) => a - b)
.reduce((acc, curr, index, arr) => {
// Getting the next element in array
const next = arr[index + 1];
if (last && last === curr) acc[acc.length - 1].push(curr);
else if (next && next === curr) acc.push([curr]);
else acc.push(curr);
// Changing the last to the curr
last = curr;
return acc;
}, []);
console.log(result);
使用 Map 对元素进行分组然后按键对 Map 条目进行排序以便完全不改变原始数组的方法
let array = [1,2,4,591,392,391,2,5,10,2,1,1,1,20,20];
const answer = (arr) =>{
const m = new Map();
arr.forEach(n => m.set(n, (m.get(n) || []).concat(n)));
return [...m.entries()].sort(([a],[b])=> a-b)
.map(([k,v]) => v.length > 1 ? v : v[0])
}
console.log(answer(array))
另一种选择。首先将每个数字压入对象的适当数组,然后根据需要将对象转换为结果数组。
let arr = [1,2,4,591,392,391,2,5,10,2,1,1,1,20,20];
const obj = {}, res = [];
for(e of arr) !obj[e] ? obj[e] = [e] : obj[e].push(e);
for(a in obj) obj[a].length === 1 ? res.push(obj[a][0]) : res.push(obj[a]);
console.log(res);
有没有办法让我的代码更简单?
仅供参考,我是初学者,我只学习了 JavaScript 一周。
谢谢!
let array = [1,2,4,591,392,391,2,5,10,2,1,1,1,20,20];
// from above to [[1, 1, 1, 1], [2, 2, 2], 4, 5, 10, [20, 20], 391, 392, 591]
const answer = (arr) => {
arr.sort((a, b) => {
return a - b;
});
let counter = 0;
arr.forEach((num, i) => {
if (arr[i] === arr[i+1]) {
counter++;
} else if (arr[i] !== arr[i + 1] && arr[i] === arr[i-1]) {
arr[i-counter] = arr.slice(i-counter, i + 1);
counter = 0;
}
});
arr.forEach((num, i) => {
while (arr[i][0] && arr[i][0] === arr[i + 1]) {
arr.splice(i + 1, 1);
}
});
return arr;
}
const newArray = answer(array);
console.log(newArray);
你可以简单点,先排序再分组。
let array = [1, 2, 4, 591, 392, 391, 2, 5, 10, 2, 1, 1, 1, 20, 20],
last = null;
const result = array
.sort((a, b) => a - b)
.reduce((acc, curr, index, arr) => {
// Getting the next element in array
const next = arr[index + 1];
if (last && last === curr) acc[acc.length - 1].push(curr);
else if (next && next === curr) acc.push([curr]);
else acc.push(curr);
// Changing the last to the curr
last = curr;
return acc;
}, []);
console.log(result);
使用 Map 对元素进行分组然后按键对 Map 条目进行排序以便完全不改变原始数组的方法
let array = [1,2,4,591,392,391,2,5,10,2,1,1,1,20,20];
const answer = (arr) =>{
const m = new Map();
arr.forEach(n => m.set(n, (m.get(n) || []).concat(n)));
return [...m.entries()].sort(([a],[b])=> a-b)
.map(([k,v]) => v.length > 1 ? v : v[0])
}
console.log(answer(array))
另一种选择。首先将每个数字压入对象的适当数组,然后根据需要将对象转换为结果数组。
let arr = [1,2,4,591,392,391,2,5,10,2,1,1,1,20,20];
const obj = {}, res = [];
for(e of arr) !obj[e] ? obj[e] = [e] : obj[e].push(e);
for(a in obj) obj[a].length === 1 ? res.push(obj[a][0]) : res.push(obj[a]);
console.log(res);