如何使用一次性泛型创建类型别名？

Question

我希望创建一个类型别名，它可以采用别名中实际未使用的泛型。原因是为了自记录代码，我知道没有类型检查器能够实际检查它。这就是我的意思：

from typing import TypeVar, Dict, Any

from dataclasses import dataclass
from dataclasses_json import dataclass_json, DataClassJsonMixin


JSON = Dict[str, Any]  # Good enough json type for this demo
T = TypeVar("T", bound=DataClassJsonMixin)
JSONOf = JSON[T]  # <-- mypy Problem: JSON takes no generic arguments

@dataclass_json   # this just provides to_json/from_json to dataclasses, not important for question
@dataclass
class Person:
    name: str
    age: int

def add_person_to_db(person: JSONOf[Person]):
    # just from reading the signature the user now knows what the input is
    # If I just put JSON as a type, it is unclear
    ...

问题是JSON类型别名没有使用泛型参数，所以收不到。我需要在别名定义中使用它而不用实际对它做任何事情。我尝试使用 PEP-593 Annotated 类型执行此操作，但它也不起作用（我可以像下面这样定义它，但它仍然不期望通用参数）：

from typing import Annotated

JSONOf = Annotated[JSON, T]

我需要做类似的事情（这不存在）：

from typing import ThrowAwayGeneric

JSONOf = ThrowAwayGeneric[JSON, T]

有没有可能得到类似于类型检查的东西？再一次：我实际上对 json 数据的类型检查不感兴趣，我只是想提供一个可读的函数签名。如果完全没问题，在实际类型检查时使用 Dict[str, Any]。

那种蛮力方法当然是为每种类型定义一个别名，但是由于有很多这样的类型，这变得很乏味。

JSONOfPerson = JSON

Answer 1

我想出了一些解决方案：

将 JSONOf 与另一种采用泛型的类型合并，将这种类型设计成一种永远不会匹配任何东西的方式，例如带有可变键的 Dict :

JSONOf = Union[JSON, Dict[List, T]] # List could be any mutable, including JSON itself

相同的方法，结合自定义泛型 class:

class JSONFrom(Generic[T]): pass  # Name was chosen to look nice on mypy errors
JSONOf = Union[JSON, JSONFrom[T]]

我们来测试一下：

from typing import Generic, TypeVar, Dict, Any, Union

class DataClassJsonMixin: ...
class Person(DataClassJsonMixin): ...
JSON = Dict[str, Any]  # Good enough json type for this demo
T = TypeVar("T", bound=DataClassJsonMixin)

# Solution 1: Union with impossible type that takes a Generic
# JSONOf = Union[JSON, Dict[JSON, T]]

# Solution 2: Union with custom generic class
class JSONFrom(Generic[T]):
    # just a crude failsafe to prohibit instantiation
    # could be improved with __new__, __init_subclasses__, etc
    def __init__(self):
        raise TypeError("Just dont!")

JSONOf = Union[JSON, JSONFrom[T]]

def add_person_to_db(person: JSONOf[Person]):
    print(person)
    try: reveal_type(person)
    except NameError: pass

add_person_to_db({'id': 1234, 'name': 'Someone'})  # Checks
add_person_to_db("Not a JSON")       # Check error by JSON
add_person_to_db(Person())           # Make sure it does not accept Person
try: someone: JSONFrom = JSONFrom()  # Make sure it does not accept JSONFrom
except TypeError as e: print(e)      # Nice try!

$ python3 test.py 
{'id': 1234, 'name': 'Someone'}
Not a JSON
<__main__.Person object at 0x7fa258a7d128>
Just dont!

$ mypy test.py 
test.py:22: note: Revealed type is "Union[builtins.dict[builtins.str, Any], test.JSONFrom[test.Person]]"
test.py:26: error: Argument 1 to "add_person_to_db" has incompatible type "str"; expected "Union[Dict[str, Any], JSONFrom[Person]]"
test.py:27: error: Argument 1 to "add_person_to_db" has incompatible type "Person"; expected "Union[Dict[str, Any], JSONFrom[Person]]"
Found 2 errors in 1 file (checked 1 source file)

如何使用一次性泛型创建类型别名？

How to create a type alias with a throw-away generic?

python

type-hinting

mypy

python-typing

type-alias