如何从 terraform 中的本地地图中删除键值对？

Question

我有一个如下所示的本地值，我想从中删除 Mongo-S 对，因为它没有 dbv 值

merged_mongo_locals = {
      MongoA-0 = {
           az           = "ap-south-1a"
           dbv          = 50
           service_name = "MongoA"
        }
       MongoC-0 = {
           az           = "ap-south-1a"
           dbv          = 50
           service_name = "MongoC"
        }
       MongoC-1 = {
           az           = "ap-south-1b"
           dbv          = 50
           service_name = "MongoC"
        }
       MongoD-0 = {
           az           = "ap-south-1a"
           dbv          = 100
           service_name = "MongoD"
        }
       MongoD-1 = {
           az           = "ap-south-1b"
           dbv          = 100
           service_name = "MongoD"
        }
       MongoD-2 = {
           az           = "ap-south-1c"
           dbv          = 100
           service_name = "MongoD"
        }
       MongoM-0 = {
           az           = "ap-south-1a"
           dbv          = 50
           service_name = "MongoM"
        }
       MongoS-0 = {
           az           = "ap-south-1a"
           service_name = "MongoS"
        }
       MongoS-1 = {
           az           = "ap-south-1b"
           service_name = "MongoS"
        }
    }

我正在使用以下方法删除 MongoS 密钥对

输出“Mongo-ips”{ value = {for k,v in local.merged_mongo_locals: k => v if !包含（值（v），“dbv”）} }

但输出如下所示，它没有排除 MongoS 对，即使它没有 dbv 值

Changes to Outputs:
  + Mongo-ips = {
      + MongoA-0 = {
          + az           = "ap-south-1a"
          + dbv          = 50
          + service_name = "MongoA"
        }
      + MongoC-0 = {
          + az           = "ap-south-1a"
          + dbv          = 50
          + service_name = "MongoC"
        }
      + MongoC-1 = {
          + az           = "ap-south-1b"
          + dbv          = 50
          + service_name = "MongoC"
        }
      + MongoD-0 = {
          + az           = "ap-south-1a"
          + dbv          = 100
          + service_name = "MongoD"
        }
      + MongoD-1 = {
          + az           = "ap-south-1b"
          + dbv          = 100
          + service_name = "MongoD"
        }
      + MongoD-2 = {
          + az           = "ap-south-1c"
          + dbv          = 100
          + service_name = "MongoD"
        }
      + MongoM-0 = {
          + az           = "ap-south-1a"
          + dbv          = 50
          + service_name = "MongoM"
        }
      + MongoS-0 = {
          + az           = "ap-south-1a"
          + service_name = "MongoS"
        }
      + MongoS-1 = {
          + az           = "ap-south-1b"
          + service_name = "MongoS"
        }
    }

请指导我这里有什么问题

Answer 1

这应该对你有帮助。

output "Mongo-ips" {
  value = { for k, v in local.merged_mongo_locals : k => v if contains(keys(v), "dbv") }
}

如何从 terraform 中的本地地图中删除键值对？

how to remove a key value pair from local map in terraform?

local-variables

terraform

terraform-provider-azure