如何按公共 属性 对对象数组进行分组并将其他属性放在一起
How to group array of objects by common property and put other properties together
我有一组这样的对象
const statuses = [
{time: '21/1/1990', 'Status.sold': 8848},
{time: '21/1/1990', 'Status.reserved': 8804},
{time: '21/1/1991', 'Status.reserved': 8756},
{time: '21/1/1991', 'Status.sold': 8732},
{time: '21/1/1992', 'Status.killed': 8691},
{time: '21/1/1992', 'Status.sold': 8620},
{time: '21/1/1993', 'Status.held': 8511},
{time: '21/1/1993', 'Status.killed': 8511},
{time: '21/1/1994', 'Status.sold': 8498},
];
我想要实现的是将所有 Status.
属性放在一起并按 time
属性 分组,这对所有对象都是通用的。所以最后的结果会是这样
const statuses = [
{time: '21/1/1990', sold: 8848, killed: 0, reserved: 8804, held: 0},
{time: '21/1/1991', sold: 8732, killed: 0, reserved: 8756, held: 0},
{time: '21/1/1992', sold: 8620, killed: 8691, reserved: 0, held: 0},
{time: '21/1/1993', sold: 0, killed: 8511, reserved: 0, held: 8511},
{time: '21/1/1994', sold: 8498, killed: 0, reserved: 0, held: 0},
];
我试过这样的东西
const result = statuses.map((obj) => {
return { ...obj,
sold: obj['Status.sold'] ? obj['Status.sold'] : 0,
reserved: obj['Status.reserved'] ? obj['Status.reserved'] : 0,
killed: obj['Status.killed'] ? obj['Status.killed'] : 0,
held: obj['Status.held'] ? obj['Status.held'] : 0
};
});
但我不确定如何按 time
对它们进行分组。如何将 reduce 方法与此代码结合使用?提前致谢!
您可以将对象按 time
进行分组。
const
statuses = [{ time: '21/1/1990', 'Status.sold': 8848 }, { time: '21/1/1990', 'Status.reserved': 8804 }, { time: '21/1/1991', 'Status.reserved': 8756 }, { time: '21/1/1991', 'Status.sold': 8732 }, { time: '21/1/1992', 'Status.killed': 8691 }, { time: '21/1/1992', 'Status.sold': 8620 }, { time: '21/1/1993', 'Status.held': 8511 }, { time: '21/1/1993', 'Status.killed': 8511 }, { time: '21/1/1994', 'Status.sold': 8498 }],
result = Object.values(statuses.reduce((r, { time, ...o }) => {
r[time] ??= { time, sold: 0, killed: 0, reserved: 0, held: 0 };
Object.entries(o).forEach(([k, v]) => r[time][k.slice(7)] += v);
return r;
}, {}));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
试试这个:
const statuses = [
{time: '21/1/1990', 'Status.sold': 8848},
{time: '21/1/1990', 'Status.reserved': 8804},
{time: '21/1/1991', 'Status.reserved': 8756},
{time: '21/1/1991', 'Status.sold': 8732},
{time: '21/1/1992', 'Status.killed': 8691},
{time: '21/1/1992', 'Status.sold': 8620},
{time: '21/1/1993', 'Status.held': 8511},
{time: '21/1/1993', 'Status.killed': 8511},
{time: '21/1/1994', 'Status.sold': 8498},
];
const result = [];
let obj = {};
for (let i = 0; i < statuses.length; i++) {
const status = statuses[i];
if (status.time != obj.time) {
if (i != 0) result.push(obj);
obj = {
time: status.time,
sold: 0,
reserved: 0,
killed: 0,
held: 0,
}
}
if (status['Status.sold']) obj.sold += status['Status.sold'];
if (status['Status.reserved']) obj.reserved += status['Status.reserved'];
if (status['Status.killed']) obj.killed += status['Status.killed'];
if (status['Status.held']) obj.held += status['Status.held'];
}
result.push(obj);
console.log(result);
我有一组这样的对象
const statuses = [
{time: '21/1/1990', 'Status.sold': 8848},
{time: '21/1/1990', 'Status.reserved': 8804},
{time: '21/1/1991', 'Status.reserved': 8756},
{time: '21/1/1991', 'Status.sold': 8732},
{time: '21/1/1992', 'Status.killed': 8691},
{time: '21/1/1992', 'Status.sold': 8620},
{time: '21/1/1993', 'Status.held': 8511},
{time: '21/1/1993', 'Status.killed': 8511},
{time: '21/1/1994', 'Status.sold': 8498},
];
我想要实现的是将所有 Status.
属性放在一起并按 time
属性 分组,这对所有对象都是通用的。所以最后的结果会是这样
const statuses = [
{time: '21/1/1990', sold: 8848, killed: 0, reserved: 8804, held: 0},
{time: '21/1/1991', sold: 8732, killed: 0, reserved: 8756, held: 0},
{time: '21/1/1992', sold: 8620, killed: 8691, reserved: 0, held: 0},
{time: '21/1/1993', sold: 0, killed: 8511, reserved: 0, held: 8511},
{time: '21/1/1994', sold: 8498, killed: 0, reserved: 0, held: 0},
];
我试过这样的东西
const result = statuses.map((obj) => {
return { ...obj,
sold: obj['Status.sold'] ? obj['Status.sold'] : 0,
reserved: obj['Status.reserved'] ? obj['Status.reserved'] : 0,
killed: obj['Status.killed'] ? obj['Status.killed'] : 0,
held: obj['Status.held'] ? obj['Status.held'] : 0
};
});
但我不确定如何按 time
对它们进行分组。如何将 reduce 方法与此代码结合使用?提前致谢!
您可以将对象按 time
进行分组。
const
statuses = [{ time: '21/1/1990', 'Status.sold': 8848 }, { time: '21/1/1990', 'Status.reserved': 8804 }, { time: '21/1/1991', 'Status.reserved': 8756 }, { time: '21/1/1991', 'Status.sold': 8732 }, { time: '21/1/1992', 'Status.killed': 8691 }, { time: '21/1/1992', 'Status.sold': 8620 }, { time: '21/1/1993', 'Status.held': 8511 }, { time: '21/1/1993', 'Status.killed': 8511 }, { time: '21/1/1994', 'Status.sold': 8498 }],
result = Object.values(statuses.reduce((r, { time, ...o }) => {
r[time] ??= { time, sold: 0, killed: 0, reserved: 0, held: 0 };
Object.entries(o).forEach(([k, v]) => r[time][k.slice(7)] += v);
return r;
}, {}));
console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }
试试这个:
const statuses = [
{time: '21/1/1990', 'Status.sold': 8848},
{time: '21/1/1990', 'Status.reserved': 8804},
{time: '21/1/1991', 'Status.reserved': 8756},
{time: '21/1/1991', 'Status.sold': 8732},
{time: '21/1/1992', 'Status.killed': 8691},
{time: '21/1/1992', 'Status.sold': 8620},
{time: '21/1/1993', 'Status.held': 8511},
{time: '21/1/1993', 'Status.killed': 8511},
{time: '21/1/1994', 'Status.sold': 8498},
];
const result = [];
let obj = {};
for (let i = 0; i < statuses.length; i++) {
const status = statuses[i];
if (status.time != obj.time) {
if (i != 0) result.push(obj);
obj = {
time: status.time,
sold: 0,
reserved: 0,
killed: 0,
held: 0,
}
}
if (status['Status.sold']) obj.sold += status['Status.sold'];
if (status['Status.reserved']) obj.reserved += status['Status.reserved'];
if (status['Status.killed']) obj.killed += status['Status.killed'];
if (status['Status.held']) obj.held += status['Status.held'];
}
result.push(obj);
console.log(result);