为什么这个无限循环 - Bash 中的简单游戏脚本

Question

编写一个简单的游戏脚本来猜出 42 的正确数字。

我在 for/else 语句中遇到无限循环。有人可以告诉我为什么吗？我对 Bash

非常陌生

谢谢

    #!/bin/bash

read -p "Please pick a number between 1 and 100: " x
q=exit
while true 
do
if [ "$x" = "q" ]
    then
        exit
      

fi
#done
if  [ "$x" -gt "42" ]; then 
echo -e "That number is too high!" 
else read -p "try again :" 

fi
if [ "$x" -lt "42" ]; 
then echo -e "That number is too low!" 
else read -p "try again :"
fi
if [ "$x" = "42" ] ; 
then echo -e "You are Correct!!!" 
else read -p "try again :"
fi
done
exit

Answer 1

此行填充 $x:

read -p "Please pick a number between 1 and 100: " x

此行填充 $REPLY:

read -p "try again :"

为什么这个无限循环 - Bash 中的简单游戏脚本

Why is this Infinite Looping - Simple Game script in Bash

bash

loops

infinite