我如何在困难的数组中计算总计

Question

我需要不同任务的帮助（对我来说不同，因为我是 JS 新手）我有数组：

let results = [
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":40271011,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":4815050,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    },
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":10271011,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":1815050,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    }
]

我必须得到这样的结果：

let result = [
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":X1,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":X2,"timeP":0,"speed":"170","shod":false,"reason":""}
        ],
        "total":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":X1,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":X2,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    },
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":Y1,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":Y2,"timeP":0,"speed":"170","shod":false,"reason":""}
        ],
        "total":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":Y1+X1,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":Y2+X2,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    }
]

我没有任何想法，结果可能会超过 2。在每一步上，我必须有当前总步数 + 之前的步数

Answer 1

你可以这样做：

      results.forEach((ele,index)=>{
let total = results[index].results;
for(let i = 0;i<=index;i++){
results[index].results.forEach((element,index)=>{
total[index].time += element.time;
})

}
results[index].total=total;
    })

我想这应该行得通！

更新：

上面代码中存在参考问题，解决方法如下：

var resultsCopy = JSON.parse(JSON.stringify(results));
resultsCopy.forEach((ele,index)=>{
let total = resultsCopy[index].results;
for(let i = 0;i<=index;i++){
resultsCopy[index].results.forEach((element,index)=>{
total[index].time += element.time;
})

}
results[index].total=total;
    })

Answer 2

使用数组保存累计次数。然后，您可以通过复制相应的 results 数组并将 time 属性替换为累计次数来创建 time 数组。

let results = [
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":40271011,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":4815050,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    },
    {
        "id": "su-1617788623816",
        "name": "СУ 2 Мельница",
        "dist": "57",
        "results":
        [
            {"crew":"13","disc":"60414658612aea0018a1f08e","time":10271011,"timeP":0,"speed":"111","shod":false,"reason":""},
            {"crew":"52","disc":"60414658612aea0018a1f08e","time":1815050,"timeP":0,"speed":"170","shod":false,"reason":""}
        ]
    }
]


let total_time = Array(results[0].results.length).fill(0);

let result = results.map(res => {
  let time = res.results.map((r, i) => {
    total_time[i] += r.time;
    return { ...r, time: total_time[i]
    }
  });
  return { ...res, time: time
  };
});

console.log(result);

Answer 3

首先定义函数：

function reducer(acc, item) {
  let totals = !acc.length ? [...item.results] : [
    {...item.results[0], time: item.results[0].time + acc[acc.length - 1].results[0].time},
    {...item.results[1], time: item.results[1].time + acc[acc.length - 1].results[1].time},
  ];
  acc.push({...item, totals});
  return acc;
}

然后像这样使用它：

let resultWithTotals = results.reduce(reducer, []);

Answer 4

result[0]["total"] = result[0].results; 

for (let i = 1; i < result.length; i++) {
    let newTotal = JSON.parse(JSON.stringify(result[i - 1]["total"]));
    for (let j = 0; newTotal && j < newTotal.length; j++) {
        newTotal[j].time += result[i].results[j].time; // assuming your X1, Y1, X2, Y2 are numbers
    }
    result[i]["total"] = newTotal;
}

console.log(result);

我如何在困难的数组中计算总计

How i can make Totals in difficult array

javascript

arrays

mapreduce

node.js