Roblox：如何编写 VectorForce 脚本

Question

我刚接触 Roblox（2 天）Lua，所以请不要咬我太紧.. =)

我想做的是为我也从代码实例化的部分编写 VectorForce 脚本。模拟中Attachment和VectorForce确实创建了，但是没有任何预期的效果。

拜托，看看我的脚本，告诉我哪里需要挖掘。

local sandblock = script.Parent
local sandblock_health = 5

local function blockJump(object)
    local jump_att = Instance.new("Attachment", object)
    local jump_force = Instance.new("VectorForce", object)
    jump_force.ApplyAtCenterOfMass = true
    jump_force.Attachment0 = jump_att
    jump_force.RelativeTo = Enum.ActuatorRelativeTo.World
    jump_force.Force = Vector3.new(10,1000,-10)
    jump_force.Enabled = true
    -- here: what is the difference between Enabled and Active?
    --jump_force.Active = true
end

local function onTouch(object)
    --print("К блоку прикоснулся "..object.Name)
    if object.Name == "Handle" then
        sandblock_health = sandblock_health - 1
        print(sandblock_health)
        
        if sandblock_health < 1 then
            local sandblock_drop1 = Instance.new("Part", workspace)
            sandblock_drop1.Size = Vector3.new(2,2,2)
            sandblock_drop1.Position = sandblock.Position + Vector3.new(0,5,-1)
            blockJump(sandblock_drop1)
            sandblock_drop1.Material = "Metal"
            sandblock_drop1.BrickColor = BrickColor.new("Gold")
            sandblock_drop1.Name = "Gold"
            
            print("Вы добыли "..sandblock_drop1.Name)
            sandblock:Destroy()
        end
    end
end

sandblock.Touched:Connect(onTouch)

Answer 1

问题似乎是当您创建 onTouch 函数时，您有一个参数：object。但是，当您在触摸该部件的播放器上调用该函数时，您没有输入任何参数：sandblock.Touched:Connect(onTouch)。要解决此问题，请执行以下操作：sandblock.Touched:Connect(onTouch(<object_parameter>))

Answer 2

解决了。在我的力矢量中，工作区的重力与零件质量的乘积远高于 1000。

下面的代码按预期工作：

jump_force.Force = Vector3.new(10, game.Workspace.Gravity * object.Mass * 1.35, -10)
jump_force.Enabled = true
wait(0.4)
jump_force.Enabled = false

Roblox：如何编写 VectorForce 脚本

Roblox: how to script VectorForce

lua

roblox