如何通过连接 table 获得不同的值？

Question

我打算按输入值过滤，但是当我执行此查询时，我得到了一些重复值！

    @Query("SELECT  DISTINCT inter FROM Intermediary inter WHERE inter.country=?1 and inter.isGood<>?2 " +
            "and inter.company.name like %?3% " +
            "or inter.company.identity like %?3% " +
            "or inter.company.client like %?3% " +
            "order by inter.createdAt DESC")
    Page<Intermediary> findAllByCompanyAndSearchValue(Country country, Integer isGood, String searchValue, Pageable pageable);

// Intermediary Entity 
{
   // ... Other attributes
  @ManyToOne(optional = false)
    private Company company;
}

// comapny Entity
{
    @OneToMany(mappedBy = "company")
    @JsonIgnore
    private List<Intermediary> intermediaries;

}

Answer 1

尝试在“或”条件周围添加括号，以避免返回满足任何可能的“and/or”组合的行所产生的重复项：

"or (inter.company.identity like %?3% " +
"or inter.company.client like %?3% )" +

如何通过连接 table 获得不同的值？

How to get Distinct values with joined table?

sql

database

hql

spring-data-jpa

spring-boot