MySQL 查询 - 待批准好友/用户与好友之间的关系
MySQL Query - Pending Friends Approval / Relationship between user & friends
我有两个table:
- g_relationships (id,request_id,receiver_id,状态,已批准)
- g_users(其中包含:id、用户名...)
我很难进行添加临时列的查询,检查 userid: 4 是否存在于 request_id 或 receiver_id 列中,并获取另一个用户 id 并从 g_users 并将其添加到临时列。
例如:假设我的用户 ID 为 4。然后我想 select g_relationships,并与 g_users 左连接,并添加一个列来检查我的用户 ID ( 4) 在 request_id 或 receiver_id 列中,并获取不是我的用户 ID,并检查它是哪个用户名并填充新列。
例如:正确的结果应该是这样的:(如果我收到好友请求)
id
request_id
receiver_id
状态
批准
朋友(new_column)
1
3
4
朋友
没有
新
但如果我是发送好友请求的人,它会看起来像这样
id
request_id
receiver_id
状态
批准
朋友(new_column)
1
4
3
朋友
没有
新
换句话说,查询应该始终检查我没有出现的列,并获取该用户 ID,然后检查 g_users table 并将那里的用户名放入 friend列。
这是我到目前为止的想法,但这只检查 request_id 不是 4,也不会用用户名填充临时列“friend”:/
SELECT *, ("friend" = CASE WHEN request_id != 4 THEN END) as friend_id
FROM `g_relationships`
LEFT JOIN g_users
ON g_relationship.request_id = g_users.id
WHERE request_id = 4 OR receiver_id = 4
AND status = "friend"
AND approved = "no"
有什么建议吗?
你试过这个吗?它将加入两个 ID 中的任何一个。
...
LEFT JOIN g_users ON ( g_relationship.request_id = g_users.id OR
g_relationship.receiver_id = g_users.id )
WHERE g_users.id = 4
我写了这两种方式。两者都对 g_users table 使用额外的 JOIN。第一个是一个单一的查询,可以让你得到你正在寻找的输出,而第二个(在我看来)更具可读性但使用 UNION 并且在技术上是两个查询。
它们给出相同的输出。
沙盒设置:
CREATE TABLE g_relationships (
id INT PRIMARY KEY,
request_id INT,
receiver_id INT,
status VARCHAR(10),
approved VARCHAR(10)
);
CREATE TABLE g_users (
id INT PRIMARY KEY,
username VARCHAR(20)
);
INSERT INTO g_users (id, username) VALUES
(1, "Jane"),
(2, "Bob"),
(3, "Sally"),
(4, "Frank");
INSERT INTO g_relationships (id, request_id, receiver_id, status, approved) VALUES
(1, 1, 3, "Friend", "No"),
(2, 1, 4, "Enemy", "No"),
(3, 4, 3, "Friend", "Yes"),
(4, 4, 2, "Friend", "Yes");
超级加入:
SELECT u.id, rel.request_id, rel.receiver_id, rel.status, rel.approved, u2.username AS FriendName
FROM g_relationships AS rel
JOIN g_users AS u
ON (rel.request_id = u.id OR rel.receiver_id = u.id)
JOIN g_users AS u2
ON (rel.request_id = u2.id OR rel.receiver_id = u2.id)
WHERE u.id != u2.id
AND u.id = 4;
联盟:
SELECT u.id, rel.request_id, rel.receiver_id, rel.status, rel.approved, u2.username AS FriendName
FROM g_relationships AS rel
JOIN g_users AS u
ON rel.request_id = u.id
JOIN g_users AS u2
ON rel.receiver_id = u2.id
WHERE u.id = 4
UNION
SELECT u.id, rel.request_id, rel.receiver_id, rel.status, rel.approved, u2.username AS FriendName
FROM g_relationships AS rel
JOIN g_users AS u
ON rel.receiver_id = u.id
JOIN g_users AS u2
ON rel.request_id = u2.id
WHERE u.id = 4;
我有两个table:
- g_relationships (id,request_id,receiver_id,状态,已批准)
- g_users(其中包含:id、用户名...)
我很难进行添加临时列的查询,检查 userid: 4 是否存在于 request_id 或 receiver_id 列中,并获取另一个用户 id 并从 g_users 并将其添加到临时列。
例如:假设我的用户 ID 为 4。然后我想 select g_relationships,并与 g_users 左连接,并添加一个列来检查我的用户 ID ( 4) 在 request_id 或 receiver_id 列中,并获取不是我的用户 ID,并检查它是哪个用户名并填充新列。
例如:正确的结果应该是这样的:(如果我收到好友请求)
id | request_id | receiver_id | 状态 | 批准 | 朋友(new_column) |
---|---|---|---|---|---|
1 | 3 | 4 | 朋友 | 没有 | 新 |
但如果我是发送好友请求的人,它会看起来像这样
id | request_id | receiver_id | 状态 | 批准 | 朋友(new_column) |
---|---|---|---|---|---|
1 | 4 | 3 | 朋友 | 没有 | 新 |
换句话说,查询应该始终检查我没有出现的列,并获取该用户 ID,然后检查 g_users table 并将那里的用户名放入 friend列。
这是我到目前为止的想法,但这只检查 request_id 不是 4,也不会用用户名填充临时列“friend”:/
SELECT *, ("friend" = CASE WHEN request_id != 4 THEN END) as friend_id
FROM `g_relationships`
LEFT JOIN g_users
ON g_relationship.request_id = g_users.id
WHERE request_id = 4 OR receiver_id = 4
AND status = "friend"
AND approved = "no"
有什么建议吗?
你试过这个吗?它将加入两个 ID 中的任何一个。
...
LEFT JOIN g_users ON ( g_relationship.request_id = g_users.id OR
g_relationship.receiver_id = g_users.id )
WHERE g_users.id = 4
我写了这两种方式。两者都对 g_users table 使用额外的 JOIN。第一个是一个单一的查询,可以让你得到你正在寻找的输出,而第二个(在我看来)更具可读性但使用 UNION 并且在技术上是两个查询。
它们给出相同的输出。
沙盒设置:
CREATE TABLE g_relationships (
id INT PRIMARY KEY,
request_id INT,
receiver_id INT,
status VARCHAR(10),
approved VARCHAR(10)
);
CREATE TABLE g_users (
id INT PRIMARY KEY,
username VARCHAR(20)
);
INSERT INTO g_users (id, username) VALUES
(1, "Jane"),
(2, "Bob"),
(3, "Sally"),
(4, "Frank");
INSERT INTO g_relationships (id, request_id, receiver_id, status, approved) VALUES
(1, 1, 3, "Friend", "No"),
(2, 1, 4, "Enemy", "No"),
(3, 4, 3, "Friend", "Yes"),
(4, 4, 2, "Friend", "Yes");
超级加入:
SELECT u.id, rel.request_id, rel.receiver_id, rel.status, rel.approved, u2.username AS FriendName
FROM g_relationships AS rel
JOIN g_users AS u
ON (rel.request_id = u.id OR rel.receiver_id = u.id)
JOIN g_users AS u2
ON (rel.request_id = u2.id OR rel.receiver_id = u2.id)
WHERE u.id != u2.id
AND u.id = 4;
联盟:
SELECT u.id, rel.request_id, rel.receiver_id, rel.status, rel.approved, u2.username AS FriendName
FROM g_relationships AS rel
JOIN g_users AS u
ON rel.request_id = u.id
JOIN g_users AS u2
ON rel.receiver_id = u2.id
WHERE u.id = 4
UNION
SELECT u.id, rel.request_id, rel.receiver_id, rel.status, rel.approved, u2.username AS FriendName
FROM g_relationships AS rel
JOIN g_users AS u
ON rel.receiver_id = u.id
JOIN g_users AS u2
ON rel.request_id = u2.id
WHERE u.id = 4;