如何将依赖于另一个流的流映射到依赖于两个流的新模型?
How to map a stream that depends on another stream to a new model depending on both streams?
我有 2 个 Firestore 流,其中第二个依赖于第一个。我想发出依赖于来自两个流的数据的新模型。
在伪代码中你可以这样想:
// 1st stream emits some device data
final streamA = client.device(id: 0); // Stream<DeviceData>
// 2nd stream emits some metadata for the above device type
final streamB = client.deviceMetadata(type: device.type); // Stream<DeviceMetadata>
// and finally I want to receive stream of combined device (device data + metadata)
final combinedObject = Device.from(deviceData, deviceMetadata);
但是,在访问源流中的值时,我找不到将一个流映射到另一个流的有效方法。例如 .map()
我想写:
return client.device('deviceId')
.map((device) => client.deviceMetadata(type: device.type))
.map((deviceMetadata) => Device.from(???, deviceMetadata));
问题当然是我不知道如何在第二个map()
中访问device
。
我可以使用什么流转换或 rxdart
扩展来实现它?
您可以使用 rxdart 库将多个流合并为一个流https://pub.dev/documentation/rxdart/latest/rx/CombineLatestStream-class.html
好的,经过一些调整我想我找到了解决方案
// get the initial stream
final deviceStream = client.device(id: id);
// create new stream depending on the first one
final deviceTypeStream = deviceStream.flatMap( // make sure to flatten the stream so that it's not Stream<Stream<..>>
(device) => client.deviceMetadata(type: device.type),
);
// use withLatestFrom to capture the latest value from the deviceTypeStream
// and create desired object out of that
return deviceTypeStream.withLatestFrom<DeviceData, Device>(
deviceStream,
(deviceType, device) => Device(device, deviceType),
);
我有 2 个 Firestore 流,其中第二个依赖于第一个。我想发出依赖于来自两个流的数据的新模型。
在伪代码中你可以这样想:
// 1st stream emits some device data
final streamA = client.device(id: 0); // Stream<DeviceData>
// 2nd stream emits some metadata for the above device type
final streamB = client.deviceMetadata(type: device.type); // Stream<DeviceMetadata>
// and finally I want to receive stream of combined device (device data + metadata)
final combinedObject = Device.from(deviceData, deviceMetadata);
但是,在访问源流中的值时,我找不到将一个流映射到另一个流的有效方法。例如 .map()
我想写:
return client.device('deviceId')
.map((device) => client.deviceMetadata(type: device.type))
.map((deviceMetadata) => Device.from(???, deviceMetadata));
问题当然是我不知道如何在第二个map()
中访问device
。
我可以使用什么流转换或 rxdart
扩展来实现它?
您可以使用 rxdart 库将多个流合并为一个流https://pub.dev/documentation/rxdart/latest/rx/CombineLatestStream-class.html
好的,经过一些调整我想我找到了解决方案
// get the initial stream
final deviceStream = client.device(id: id);
// create new stream depending on the first one
final deviceTypeStream = deviceStream.flatMap( // make sure to flatten the stream so that it's not Stream<Stream<..>>
(device) => client.deviceMetadata(type: device.type),
);
// use withLatestFrom to capture the latest value from the deviceTypeStream
// and create desired object out of that
return deviceTypeStream.withLatestFrom<DeviceData, Device>(
deviceStream,
(deviceType, device) => Device(device, deviceType),
);