如何在命令 Shell 中创建虚拟控制器传递给组件 CakePHP 2.4.3
How to create a dummy Controller in Command Shell pass to Component CakePHP 2.4.3
我使用 CakePHP 2.4.3
我在命令中的代码ShellPhulyShell.php
<?php
App::uses('ComponentCollection', 'Controller');
App::uses('HopeeComponent', 'Controller/Component');
class PhulyShell extends AppShell {
public $components = array('Hopee');
public function initialize() {
$collection = new ComponentCollection();
$this->Hopee = new HopeeComponent($collection);
}
}
HopeeComponent.php之前是别人写的,我无权编辑。
文件里面有一段代码
public function __construct(ComponentCollection $collection, $settings = array()) {
if($this->_Controller->request != null){
$shortcut_app_flag = $this->_Controller->request->query('phuly_app');
}
}
会报错,因为没有controller $this->_Controller
Notice Error: Trying to get property of non-object in [cakephp-2.4.3/phuly/Controller/Component/HopeeComponent.php, line 112]
我知道一种解决方案是将控制器传递给它
<?php
App::uses('ComponentCollection', 'Controller');
App::uses('HopeeComponent', 'Controller/Component');
App::uses('AppController', 'Controller');
App::uses('TestController', 'Controller');
class PhulyShell extends AppShell {
public $components = array('Hopee');
public function initialize() {
$collection = new ComponentCollection();
$collection->init(new TestController);
$this->Hopee = new HopeeComponent($collection);
}
}
有效但没有显示 Notice Error,但我不想创建文件 TestController.php,我无法使用 AppController.php
有没有办法将虚拟控制器传递给组件而不在Shell命令中创建文件控制器?
谢谢大家!
我自己找到了答案,就是用Controller,我傻了没注意到这个
<?php
App::uses('ComponentCollection', 'Controller');
App::uses('HopeeComponent', 'Controller/Component');
App::uses('Controller', 'Controller');
class PhulyShell extends AppShell {
public $components = array('Hopee');
public function initialize() {
$collection = new ComponentCollection();
$collection->init(new Controller);
$this->Hopee = new HopeeComponent($collection);
}
}
我使用 CakePHP 2.4.3
我在命令中的代码ShellPhulyShell.php
<?php
App::uses('ComponentCollection', 'Controller');
App::uses('HopeeComponent', 'Controller/Component');
class PhulyShell extends AppShell {
public $components = array('Hopee');
public function initialize() {
$collection = new ComponentCollection();
$this->Hopee = new HopeeComponent($collection);
}
}
HopeeComponent.php之前是别人写的,我无权编辑。 文件里面有一段代码
public function __construct(ComponentCollection $collection, $settings = array()) {
if($this->_Controller->request != null){
$shortcut_app_flag = $this->_Controller->request->query('phuly_app');
}
}
会报错,因为没有controller $this->_Controller
Notice Error: Trying to get property of non-object in [cakephp-2.4.3/phuly/Controller/Component/HopeeComponent.php, line 112]
我知道一种解决方案是将控制器传递给它
<?php
App::uses('ComponentCollection', 'Controller');
App::uses('HopeeComponent', 'Controller/Component');
App::uses('AppController', 'Controller');
App::uses('TestController', 'Controller');
class PhulyShell extends AppShell {
public $components = array('Hopee');
public function initialize() {
$collection = new ComponentCollection();
$collection->init(new TestController);
$this->Hopee = new HopeeComponent($collection);
}
}
有效但没有显示 Notice Error,但我不想创建文件 TestController.php,我无法使用 AppController.php
有没有办法将虚拟控制器传递给组件而不在Shell命令中创建文件控制器?
谢谢大家!
我自己找到了答案,就是用Controller,我傻了没注意到这个
<?php
App::uses('ComponentCollection', 'Controller');
App::uses('HopeeComponent', 'Controller/Component');
App::uses('Controller', 'Controller');
class PhulyShell extends AppShell {
public $components = array('Hopee');
public function initialize() {
$collection = new ComponentCollection();
$collection->init(new Controller);
$this->Hopee = new HopeeComponent($collection);
}
}