按 "dataPrin" 字段对对象数组进行分组

Question

我尝试了一段时间按“dataPrin”字段对这个数组进行分组，但没有成功。

请注意，我有两个“dataPrin”字段显示相同的日期，对吧！

我想对这个数组进行分组，这样如果有两个“dataPrin”字段显示相同的日期，它们将被分组为一个，如下例所示。

是否可以为此使用 'reduce'？我想得到社区的帮助。

当前数组：

[{
    "dataPrin": "2021-05-31T16:10:28-03:00",
    "selectAll": false,
    "lancamentos": [{
            "cod_transacao": 1510,
            "num_cpf_cnpj": "11.414.555/0001-04",
            "dt_lancamamento": "2021-05-31T16:29:28-03:00",
        }]
},
{
    "dataPrin": "2021-05-29T16:30:28-03:00",
    "selectAll": false,
    "lancamentos": [{
            "cod_transacao": 1511,
            "num_cpf_cnpj": "11.414.555/0001-04",
            "dt_lancamamento": "2021-05-31T16:29:28-03:00",
        }]
},
{
    "dataPrin": "2021-05-29T16:15:28-03:00",
    "selectAll": false,
    "lancamentos": [{
            "cod_transacao": 1512,
            "num_cpf_cnpj": "11.414.555/0001-04",
            "dt_lancamamento": "2021-05-31T16:29:28-03:00",
        }]
}]

所需数组

[{
    "dataPrin": "2021-05-31T16:10:28-03:00",
    "selectAll": false,
    "lancamentos": [{
            "cod_transacao": 1510,
            "num_cpf_cnpj": "11.414.555/0001-04",
            "dt_lancamamento": "2021-05-31T16:29:28-03:00",
        }]
},
{
    "dataPrin": "2021-05-29T16:30:28-03:00",
    "selectAll": false,
    "lancamentos": [{
            "cod_transacao": 1511,
            "num_cpf_cnpj": "11.414.555/0001-04",
            "dt_lancamamento": "2021-05-31T16:29:28-03:00",
        },
        {
            "cod_transacao": 1512,
            "num_cpf_cnpj": "11.414.555/0001-04",
            "dt_lancamamento": "2021-05-31T16:29:28-03:00",
        }]
}]

Answer 1

这非常适合 reduce()。

const data = [{
    "dataPrin": "2021-05-31T16:10:28-03:00",
    "selectAll": false,
    "lancamentos": [{
      "cod_transacao": 1510,
      "num_cpf_cnpj": "11.414.555/0001-04",
      "dt_lancamamento": "2021-05-31T16:29:28-03:00",
    }]
  },
  {
    "dataPrin": "2021-05-29T16:30:28-03:00",
    "selectAll": false,
    "lancamentos": [{
      "cod_transacao": 1511,
      "num_cpf_cnpj": "11.414.555/0001-04",
      "dt_lancamamento": "2021-05-31T16:29:28-03:00",
    }]
  },
  {
    "dataPrin": "2021-05-29T16:15:28-03:00",
    "selectAll": false,
    "lancamentos": [{
      "cod_transacao": 1512,
      "num_cpf_cnpj": "11.414.555/0001-04",
      "dt_lancamamento": "2021-05-31T16:29:28-03:00",
    }]
  }
]

let ndata = data.reduce((b, a) => {
  let iden = a.dataPrin.split("T")[0];
  if (b.hasOwnProperty(iden)) a.lancamentos.forEach(l => b[iden].lancamentos.push(l));
  else b[iden] = a;
  return b
}, {})

console.log(ndata);

Answer 2

你在这里：

var data = [{
              "dataPrin": "2021-05-31T16:10:28-03:00",
              "selectAll": false,
              "lancamentos": [{
                      "cod_transacao": 1510,
                      "num_cpf_cnpj": "11.414.555/0001-04",
                      "dt_lancamamento": "2021-05-31T16:29:28-03:00",
                  }]
          },
          {
              "dataPrin": "2021-05-29T16:30:28-03:00",
              "selectAll": false,
              "lancamentos": [{
                      "cod_transacao": 1511,
                      "num_cpf_cnpj": "11.414.555/0001-04",
                      "dt_lancamamento": "2021-05-31T16:29:28-03:00",
                  }]
          },
          {
              "dataPrin": "2021-05-29T16:15:28-03:00",
              "selectAll": false,
              "lancamentos": [{
                      "cod_transacao": 1512,
                      "num_cpf_cnpj": "11.414.555/0001-04",
                      "dt_lancamamento": "2021-05-31T16:29:28-03:00",
                  }]
          }]

          const temp = data.reduce((res,item)=>{ 
            const date = item.dataPrin.split('T')[0];

            if(date in res){
              res[date].lancamentos.push(...item.lancamentos)
            }else{
              res[date] = item;
            }
            return res
          },{});
          const desired = Object.keys(temp).map(c=>temp[c])

按 "dataPrin" 字段对对象数组进行分组

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