public 字段上的 => 运算符的目的是什么？

Question

在 C# class 中对 public 字段使用 => 运算符的目的是什么？我在 GitHub 上托管的 eShopOnWeb ASP.NET 核心项目的单元测试代码中看到了这一点。它实际上是一个属性和 => 运算符引用从 getter 方法返回的值吗？有问题的代码如下所示：

using Microsoft.eShopWeb.ApplicationCore.Entities.OrderAggregate;

namespace Microsoft.eShopWeb.UnitTests.Builders
{
    public class AddressBuilder
    {
        private Address _address;
        public string TestStreet => "123 Main St.";
        public string TestCity => "Kent";
        public string TestState => "OH";
        public string TestCountry => "USA";
        public string TestZipCode => "44240";

        public AddressBuilder()
        {
            _address = WithDefaultValues();
        }
        public Address Build()
        {
            return _address;
        }
        public Address WithDefaultValues()
        {
            _address = new Address(TestStreet, TestCity, TestState, TestCountry, TestZipCode);
            return _address;
        }
    }
}

Answer 1

拿这个class:

public class Foo
{
    public int Bar { get; } = 42;
    public int Qaz => 42;
}

反编译后输出如下：

public class Foo
{
    [CompilerGenerated]
    [DebuggerBrowsable(DebuggerBrowsableState.Never)]
    private readonly int <Bar>k__BackingField = 42;

    public int Bar
    {
        [CompilerGenerated]
        get
        {
            return <Bar>k__BackingField;
        }
    }

    public int Qaz
    {
        get
        {
            return 42;
        }
    }
}

您正在查看仅 get 个属性的 shorthand。

public 字段上的 => 运算符的目的是什么？

What is the purpose of the => operator on public fields?

c#

public-fields