代码运行时播放器不显示？

Question

代码有一些错误，但我不明白。我试图搜索它们，但一无所获！

错误是：

  File "d:\Python\sendsend\client.py", line 67, in <module>
    main()
  File "d:\Python\sendsend\client.py", line 64, in main
    redrawWindow(win,p)
  File "d:\Python\sendsend\client.py", line 50, in redrawWindow
    pygame.display.update()

密码是：

import pygame

                                                    
width = 500
height = 500
win = pygame.display.set_mode ((width, height))
pygame.init()
pygame.display.set_caption("Client")

clientNumber = 0

class Player:
    def __init__(self, x, y, width, height, color):
        self.x = x
        self.y = y
        self.width = width
        self.height = height
        self.color = color
        self.rect = (x,y,width,height)
        self.val = 3
    
    def draw(self,win):
        pygame.init()
        pygame.draw.rect(win, self.color, self.rect)

    def move(self):
        pygame.init()
        keys = pygame.key.get_pressed()

        if keys[pygame.K_LEFT]:
            self.x -= self.vel

        if keys[pygame.K_RIGHT]:
            self.x += self.vel

        if keys[pygame.K_DOWN]:
            self.y -= self.vel

        if keys[pygame.K_UP]:
            self.y += self.vel

        self.rect = self.x,self.y,self.width,self.height

     


def redrawWindow(win,player):   
    player.draw(win)                              
    win.fill((0,0,255))
    pygame.display.update()

def main () :                                       
    run = True
    p = Player(50,50,100,100,(0,255,0))

    while run:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:           
                run = False
                pygame.init()
                pygame.quit()
        
        pygame.init()
        p.move()
        redrawWindow(win,p)    

pygame.init()
main()

我正在尝试借助本教程编写在线游戏代码：

https://www.youtube.com/watch?v=McoDjOCb2Zo&t=22s

顺便说一句，这是我的第一个 post 如果我有任何错误，请原谅！

Answer 1

Player.__init__ 中有错别字。 self.val 需要 self.vel:

~~self.val = 3~~

self.vel = 3

您需要在清除背景后和更新屏幕之前绘制播放器：

def redrawWindow(win,player):  
    win.fill((0,0,255)) 
    player.draw(win)                              
    pygame.display.update()

使用pygame.time.Clock控制每秒帧数，从而控制游戏速度。

方法tick() of a pygame.time.Clock object, delays the game in that way, that every iteration of the loop consumes the same period of time. See pygame.time.Clock.tick():

This method should be called once per frame.

def main () :                                       
    run = True
    p = Player(50,50,100,100,(0,255,0))

    clock = pygame.time.Clock()
    while run:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:           
                run = False
                pygame.init()
                pygame.quit()
        
        pygame.init()
        p.move()
        redrawWindow(win,p)
        clock.tick(60)    

pygame.init()
main()

典型的 PyGame 应用程序循环必须：

通过 pygame.event.pump() or pygame.event.get().
根据输入事件和时间（分别为帧）更新对象的游戏状态和位置
清除整个显示或绘制背景
绘制整个场景（blit 所有对象）
通过pygame.display.update() or pygame.display.flip()
限制每秒帧数以限制 CPU 使用 pygame.time.Clock.tick

代码运行时播放器不显示？

Player not displaying when the code runs?

python

pygame

display