使用一行代码从两个单独的列表生成一个新列表

Question

我正在尝试一项要求您执行的练习：

write a program that returns a list that contains only the elements that are common between the lists (without duplicates). Make sure your program works on two lists of different sizes.

我能够做到这一点，但额外的挑战之一是：

Write this in one line of Python

我想出了以下代码：

list_1 = [1, 1, 2, 3, 3, 3, 3, 3, 3, 3, 89]
list_2 = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 3, 3, 13]
newList = []

newList = [x for x in list_1 if x in list_2 if x not in newList] #attempting one line

print(newList)
newList = []

for x in list_1:
    if x in list_2 and x not in newList:
        newList.append(x)

print(newList)

我得到以下结果：

[1, 1, 2, 3, 3, 3, 3, 3, 3, 3]
[1, 2, 3]

我的单行列表理解似乎失败了，有人能指出这是为什么吗？

Answer 1

一种基本方法是将 newList 转换为 set，然后将其重新转换为 list

print(list(set(newList)))

或者使用不带任何循环的集合交集

print(list(set(list_1).intersection(list_2)))

使用一行代码从两个单独的列表生成一个新列表

Generating a new List from two Separate Lists with one Line of Code

python

list-comprehension

list