如何按时间间隔显示recyclerview项目?

How to show recyclerview items in time interval?

我想每 10 秒显示一次 recyclerview 项目。例如,我的 arraylist 中有 8 个项目。最初我想显示 3 个项目,然后等待 10 秒后,前三个可见项目将消失,接下来的 3 个项目将显示。如何实现?

private void addList(){
        ItemAdapter itemAdapter = new ItemAdapter();
        itemAdapter.setImage(R.drawable.cachua);
        itemAdapter.setText("Tomato");
        mList.add(itemAdapter);

        itemAdapter = new ItemAdapter();
        itemAdapter.setImage(R.drawable.bo);
        itemAdapter.setText("butter");
        mList.add(itemAdapter);

        itemAdapter = new ItemAdapter();
        itemAdapter.setImage(R.drawable.cam);
        itemAdapter.setText("oranges");
        mList.add(itemAdapter);

        mAdapter = new ListAdapter(mList, this);
        mRecycleview.setAdapter(mAdapter);
        mRecycleview.setLayoutManager(new LinearLayoutManager(this));
        mAdapter.notifyDataSetChanged();
        Log.d("anhtt","mlist : " +mList.size());
        mList.clear();


        itemAdapter = new ItemAdapter();
        itemAdapter.setImage(R.drawable.quaxoai);
        itemAdapter.setText("mango");
        mList.add(itemAdapter);

        itemAdapter = new ItemAdapter();
        itemAdapter.setImage(R.drawable.dau);
        itemAdapter.setText("strawberry");
        try {
            Thread.sleep(3000);
        } catch (InterruptedException e) {
            e.printStackTrace();
        }
        mAdapter = new ListAdapter(mList, this);
        mRecycleview.setAdapter(mAdapter);
        mRecycleview.setLayoutManager(new LinearLayoutManager(this));
        mAdapter.notifyDataSetChanged();
        Log.d("anhtt","mlist : " +mList.size());
        mList.add(itemAdapter);
        itemAdapter = new ItemAdapter();
        itemAdapter.setImage(R.drawable.tao);
        itemAdapter.setText("Apple");
        mList.add(itemAdapter);

        mList.add(itemAdapter);
        itemAdapter = new ItemAdapter();
        itemAdapter.setImage(R.drawable.oi);
        itemAdapter.setText("guava fruit");
        mList.add(itemAdapter);
    }

有趣的场景。我认为与其在适配器中添加时间延迟,不如在将数据传递给适配器的 class 中执行这些操作。尝试加载要显示的前 3 个项目,然后使用处理程序延迟 10 秒。

像这样:

 final Handler handler = new Handler(Looper.getMainLooper());
    handler.postDelayed(new Runnable() {
      @Override
      public void run() {
        //Do your code to clear list and adding next 3 items and notify your adapter
      }
    }, 10000);

在此之后,您需要清除您的列表并在列表中添加接下来的 3 个项目,并通知您的适配器数据已更新。通过这种方法,您可以实现您的用例。

您绝对应该避免在 UI 线程上使用 Thread.sleep() 以保持其畅通无阻。

阻塞 UI 线程将停止事件分派(输入、绘图事件),并且对用户而言应用程序似乎被冻结。如果您最终阻塞 UI 线程超过 5 秒,那么用户将看到一个 Application Not Responding 对话框,这会导致非常糟糕的用户体验。

对于您的用例,您可以使用 Handler 以延迟的方式将事件分派到 UI 线程

这是一个粗略的框架,可能会很有用:

public final class ScratchActivity extends AppCompatActivity {

    private static final int INTERVAL_IN_MILLIS = 10000;
    private static final int STEP = 3;

    private Handler mHandler;

    // Backing list of models to update the recycler view
    private final List<Object> mItems = new ArrayList<>();

    @Override
    public void onCreate(@Nullable Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        mHandler = new Handler(Looper.getMainLooper());
    
        /*
            Set content view for activity etc.
            Initialize recycler view, layout manager and adapter
         */
    
        updateItems(0);
    }

    // Loop periodically to derive a sublist of items to update the recycler view adapter
    private void updateItems(int index) {
        if (index >= mItems.size()) return;
    
        notifyRecyclerView(mItems.subList(index, Math.min(index + STEP, mItems.size())));
        mHandler.postDelayed(() -> updateItems(index + STEP), INTERVAL_IN_MILLIS);
    }

    private void notifyRecyclerView(List<Object> data) {
        // Replace data within the recycler view
    }
}