更改 int 变量值时遇到问题（Tic Tac Toe）

Question

这是 playerTurn 方法。

public static void playerTurn(int player) 
{
    if (player == 1)
    {
        player = 2;
   }
    else if(player == 2) { player = 1; }
}

为什么调用playerTurn方法后播放器没有变化。我尝试更改玩家 1 的初始值并弄乱 if else 语句，但它没有用。我仍然是 C# 的新手，所以我可能在其他地方做错了，但我不确定还能尝试什么。

static void Main(string[] args) //MAIN METHOD
{
    int player = 1;
    int inputNum;

    int turns = 0;

    Console.WriteLine("Player1: X");
    Console.WriteLine("Player2: O");
    Console.WriteLine("\n");
    SetField();

    openMessage(player);

    string input = Console.ReadLine();


    if (int.TryParse(input, out inputNum))
    {
        inputNum = int.Parse(input);
        turns++;
    }
    else 
    {
        Console.WriteLine("Please enter a valid input!");
    }

    switch (player) 
    {
        case 1:switch (inputNum) 
            { 
                case 1: playField[0, 0] = playerSign(player); break;
                case 2: playField[0, 1] = playerSign(player); break;
                case 3: playField[0, 2] = playerSign(player); break;
                case 4: playField[1, 0] = playerSign(player); break;
                case 5: playField[1, 1] = playerSign(player); break;
                case 6: playField[1, 2] = playerSign(player); break;
                case 7: playField[2, 0] = playerSign(player); break;
                case 8: playField[2, 1] = playerSign(player); break;
                case 9: playField[2, 2] = playerSign(player); break;
            }
            break;

        case 2:
            switch (inputNum)
            {
                case 1: playField[0, 0] = playerSign(player); break;
                case 2: playField[0, 1] = playerSign(player); break;
                case 3: playField[0, 2] = playerSign(player); break;
                case 4: playField[1, 0] = playerSign(player); break;
                case 5: playField[1, 1] = playerSign(player); break;
                case 6: playField[1, 2] = playerSign(player); break;
                case 7: playField[2, 0] = playerSign(player); break;
                case 8: playField[2, 1] = playerSign(player); break;
                case 9: playField[2, 2] = playerSign(player); break;
            }
            break;
    }

    SetField();

    Console.WriteLine(player);
    playerTurn(player);

    //player 1 turn end
    Console.WriteLine(player);
    openMessage(player);

    Console.ReadKey();
}

Answer 1

参数按值传递给此方法。因此它只获得值的副本。 Return 新值。此外，您可以简化 playerTurn 方法：

public static int playerTurn(int player)
{
    return 3 - player; // Switches player from 1 to 2 or vice-versa.
}

3 - 2 = 1。 3 - 1 = 2。用

调用它

player = playerTurn(player);

您可以通过一些数学运算以更简单的方式获得索引：

playField[(inputNum - 1) / 3, (inputNum - 1) % 3] = playerSign(player);

/ 执行整数除法，将结果截断为下一个较小的整数。 % 产生该除法的余数。

并且没有必要打开 player，因为这两种情况是相同的。这允许您用一行代码替换 31 行代码。

另请注意，您的游戏没有循环。因此，它会在第一个玩家移动后停止。

Answer 2

这个方法：

public static void playerTurn(int player) 
    {
        if (player == 1)
        {
            player = 2;
        }
        else if(player == 2) { player = 1; }
    }

复制传入的任何内容并修改副本。您需要做的是通过引用传递值：

public static void playerTurn(ref int player)
    ...

这样传递给 playerTurn 方法的任何变量都会被直接修改。

更改 int 变量值时遇到问题（Tic Tac Toe）

Having trouble changing int variable value (Tic Tac Toe)

c#

methods

tic-tac-toe