discord bot python 删除频道出错
discord bot python delete channel gives an error
我试图创建一个删除针对核弹机器人的核弹频道的命令,
这是我的代码:
async def inferno(ctx,problem):
if problem == ("channelnuke"):
channel == ("Nuke-channel")
await ctx.send("okay solving problem")
await ctx.send("Guard on, every nuke channel will be instant deleted")
while True:
await channel.delete()
但是报错discord has no attribute delete
discord.ext.commands.errors.CommandInvokeError: Command raised an exception: AttributeError: module 'discord.channel' has no attribute 'delete'
有谁知道应该怎么做吗?
async def inferno(ctx, problem):
if problem == "channelnuke":
channel == ctx.channel
await channel.delete()
await ctx.send("okay solving problem")
await ctx.send("Guard on, every nuke channel will be instant deleted")
遗憾的是,由于我的声誉不足,我无法对之前的答案发表评论。所以这是上一个答案的更新代码,现在应该可以使用了。
@client.command()
async def inferno(ctx, problem):
if problem == "channelnuke":
channel = ctx.channel # the previous answer had put (==) instead of (=)
await ctx.send("okay solving problem")
await ctx.send("Guard on, every nuke channel will be instant deleted")
await channel.delete()
如果你想添加频道,你可以通过将频道作为可选参数来实现:
@client.command()
async def inferno(ctx, problem, channel : commands.TextChannelConverter = None): # we will put the channel into an optional arguments by doing = None
if channel == None: # it will find the channel if you didn't specify the channel
channel = ctx.channel
await ctx.send("okay solving problem")
if problem == "channelnuke":
await channel.delete()
TextChannelConverter 将查看频道,您可以使用 id、频道名称或提及频道,它应该可以工作,下面将提供更多信息。
稍后谢谢我:D
我试图创建一个删除针对核弹机器人的核弹频道的命令, 这是我的代码:
async def inferno(ctx,problem):
if problem == ("channelnuke"):
channel == ("Nuke-channel")
await ctx.send("okay solving problem")
await ctx.send("Guard on, every nuke channel will be instant deleted")
while True:
await channel.delete()
但是报错discord has no attribute delete
discord.ext.commands.errors.CommandInvokeError: Command raised an exception: AttributeError: module 'discord.channel' has no attribute 'delete'
有谁知道应该怎么做吗?
async def inferno(ctx, problem):
if problem == "channelnuke":
channel == ctx.channel
await channel.delete()
await ctx.send("okay solving problem")
await ctx.send("Guard on, every nuke channel will be instant deleted")
遗憾的是,由于我的声誉不足,我无法对之前的答案发表评论。所以这是上一个答案的更新代码,现在应该可以使用了。
@client.command()
async def inferno(ctx, problem):
if problem == "channelnuke":
channel = ctx.channel # the previous answer had put (==) instead of (=)
await ctx.send("okay solving problem")
await ctx.send("Guard on, every nuke channel will be instant deleted")
await channel.delete()
如果你想添加频道,你可以通过将频道作为可选参数来实现:
@client.command()
async def inferno(ctx, problem, channel : commands.TextChannelConverter = None): # we will put the channel into an optional arguments by doing = None
if channel == None: # it will find the channel if you didn't specify the channel
channel = ctx.channel
await ctx.send("okay solving problem")
if problem == "channelnuke":
await channel.delete()
TextChannelConverter 将查看频道,您可以使用 id、频道名称或提及频道,它应该可以工作,下面将提供更多信息。
稍后谢谢我:D