正则表达式替换日期和时间

Regex to replace date and hour

谁能帮我做这个面具,日期部分没问题,但我不知道如何实现小时? 正则表达式是:(\d{2}\/)+(\d{4})\s*(\d{2}:\d{2})/

const onMask =  (v, mask) => {   
    if (!v) return;
    v = v.replace(/\D/g,'');
    switch(mask) {
        case 'datehour':
            v = v.replace(/(\d{2})(\d)/, '/');
            v = v.replace(/(\d{2})(\d)/, '/');
            v = v.replace(/(\d{4})(\d)/, ' ');
            break;
    }

使用类似

的东西

var v = '23-12-2021 12-34' 
v = v.replace(/\D+/g, ''); 
v = v.replace(/^(\d{2})(\d)/, '/');
v = v.replace(/^(\d{2}\/\d{2})(\d)/, '/');
v = v.replace(/^(\d{2}\/\d{2}\/\d{4})(\d)/, ' ');
v = v.replace(/^(\d{2}\/\d{2}\/\d{4} \d{2})(\d)/, ':');
console.log(v)

在重新格式化数据之前删除非数字字符,在预期位置添加 space/slash/colon。