如何将 Gson 与番石榴表一起使用

Question

我将我的数据存储在 Guava Table 中，需要将其保存到 JSON 文件.

我设法使 Gson#toJson 方法正常工作，但我很难将其读回 table。

有人知道我能做什么吗？

Answer 1

你应该自己写一套Serializer/Deserializers or even TypeAdapter(Factory). Here's a sample implementation based on https://github.com/acebaggins/guava-gson-serializers:

static class TableSerializer implements JsonSerializer<Table> {

    @Override
    public JsonElement serialize(Table table, Type type, JsonSerializationContext context) {
        return context.serialize(table.rowMap());
    }
}

static class TableDeserializer implements JsonDeserializer<Table<?, ?, ?>> {

    @Override
    public Table deserialize(JsonElement json, Type type, JsonDeserializationContext context) throws JsonParseException {
        Type[] typeArguments = ((ParameterizedType) type).getActualTypeArguments();
        Type parameterizedType = hashMapOf(
                typeArguments[0],
                hashMapOf(typeArguments[1], typeArguments[2]).getType()).getType();
        Map<?, Map<?, ?>> map = context.deserialize(json, parameterizedType);

        Table<Object, Object, Object> table = HashBasedTable.create();
        for (Object rowKey : map.keySet()) {
            Map<?, ?> rowMap = map.get(rowKey);
            for (Object columnKey : rowMap.keySet()) {
                Object value = rowMap.get(columnKey);
                table.put(rowKey, columnKey, value);
            }
        }
        return table;
    }
}

// see https://github.com/acebaggins/guava-gson-serializers/blob/master/src/main/java/com/baggonius/gson/immutable/Types.java
static <K, V> TypeToken<HashMap<K, V>> hashMapOf(Type key, Type value) {
    TypeParameter<K> newKeyTypeParameter = new TypeParameter<K>() {};
    TypeParameter<V> newValueTypeParameter = new TypeParameter<V>() {};
    return new TypeToken<HashMap<K, V>>() {}
            .where(newKeyTypeParameter, typeTokenOf(key))
            .where(newValueTypeParameter, typeTokenOf(value));
}

private static <E> TypeToken<E> typeTokenOf(Type type) {
    return (TypeToken<E>) TypeToken.of(type);
}

应该这样使用：

@Test
public void shouldSerializeAndDeserializeGuavaTable() {
    Table<Integer, Integer, String> table = ImmutableTable.<Integer, Integer, String>builder()
            .put(1, 1, "eleven")
            .put(1, 0, "ten")
            .put(4, 2, "forty-two")
            .build();

    Gson gson = new GsonBuilder()
            .registerTypeHierarchyAdapter(Table.class, new TableSerializer())
            .registerTypeHierarchyAdapter(Table.class, new TableDeserializer())
            .create();
    String tableAsString = gson.toJson(table); // {"1":{"1":"eleven","0":"ten"},"4":{"2":"forty-two"}}

    Table<Integer, Integer, String> deserializedTable = gson.fromJson( // {1={0=ten, 1=eleven}, 4={2=forty-two}}
            tableAsString,
            new TypeToken<Table<Integer, Integer, String>>() {}.getType());

    Assertions.assertThat(deserializedTable)
            .hasSize(3)
            .containsCell(1, 1, "eleven")
            .containsCell(1, 0, "ten")
            .containsCell(4, 2, "forty-two");
}

如果我有空余时间，我可能会创建一个 PR 到 https://github.com/acebaggins/guava-gson-serializers，其中包含针对 Table（反）序列化的经过适当测试的更改。

如何将 Gson 与番石榴表一起使用

How to use Gson with guava tables

java

gson

guava