去如何响应csv文件？

Question

我正在用 Go 创建一个服务器，我想用 CSV 文件响应。

下面是我写的，这不会导致浏览器下载CSV文件。如何提示浏览器下载 CSV 文件？

import "github.com/gocarina/gocsv"

type Test struct {
    ID   int
    Name string
    Delete string
}

router.Get("/test", func(writer http.ResponseWriter, request *http.Request) {
    writer.WriteHeader(http.StatusOK)


    tests := []*Test{
        {
            ID:   1,
            Name: "a",
            Delete: "delete",
        },
        {
            ID:   2,
            Name: "b",
            Delete: "delete",
        },
    }

    w := multipart.NewWriter(writer)
    ww, err := w.CreateFormFile("file.csv", "file.csv")
    if err != nil {
        logger.Error("CreateFormfile", zap.Error(err))
    }
    gocsv.Marshal(tests, ww)

})

Answer 1

如果您想告诉浏览器将响应显示为要下载的文件，您可以使用 Content-Disposition header:

rw.Header().Add("Content-Disposition", `attachment; filename="test.csv"`)

就输出CSV文档本身而言，我不确定你想通过多部分编码响应来实现什么，但你应该直接将 CSV 文件编组到原始 HTTP 响应编写器中：

router.Get("/test", func(rw http.ResponseWriter, req *http.Request) {

        tests := []*Test{
            {
                ID:   1,
                Name: "a",
                Delete: "delete",
            },
            {
                ID:   2,
                Name: "b",
                Delete: "delete",
            },
        }

        gocsv.Marshal(tests, rw)

})

去如何响应csv文件？

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