想在 python 3+ 中只使用一个用户定义的输入和输出函数

want to use only one user define function for input and output in python 3+

from numpy import*
def row():
    for i in range(len(a)):
        for j in range(len(a[i])):
            t = [i, j]
            inp(*t)
def inp(*m):
    a[m] = int(input(f"entert the element of {m} = "))
    out(*m)
def out(*o):
    print(a[o])
a = zeros((1,2), dtype = int)
row()

输出显示如下:

enter the element of (0, 0) = 2
2
enter the element of (0, 1) = 3
3

但我想像这样显示输出

像这样一次输入

enter the element of (0, 0) = 2
enter the element of (0, 1) = 3

这样一次输出

2
3

可以通过创建两个单独的 for 循环或两个用于输入和输出的函数来实现 但我的问题是:我怎样才能只创建一个函数

def row():
    for i in range(len(a)):
        for j in range(len(a[i])):
            t = [i, j]
            inp(*t)

与其立即打印输出,不如保存值并在完成收集后打印它们:

import numpy as np

def row(a):
    values = []
    for i in range(len(a)):
        for j in range(len(a[i])):
            value = get_input(a, i, j)
            values.append(value)
    for value in values:
        print(value)

def get_input(a, *m):
    a[m] = int(input(f"enter the element of {m} = "))
    return a[m]

a = np.zeros((1,2), dtype = int)
row(a)

给予

enter the element of (0, 0) = 1
enter the element of (0, 1) = 2
1
2

但是,还有一种更简单的方法:因为您还在矩阵中设置了新元素,所以您不必单独保存它们,只需打印出矩阵值即可:

for item in a.ravel():
    print(item)