如何在 Promise 中包装函数调用
How to wrap function call inside of Promise
导出所需模块并设置变量后
let AWS = require("aws-sdk");
const AmazonCognitoIdentity = require('amazon-cognito-identity-js');
const USER_POOL_ID = 'us-east-1_vkXRQuP4U';
const CLIENT_ID = 'mipa4trls0l7323om33mlk80e8';
const poolData = {
UserPoolId : USER_POOL_ID, ClientId : CLIENT_ID
};
const POOL = new AmazonCognitoIdentity.CognitoUserPool(poolData);
let email = "my.email@domain.com";
let password = "My.Password!";
我可以继续调用 signUp
命令:
POOL.signUp(email, password, [], null, function(err, result) {
console.log('...result:', result);
});
而且效果很好。接下来我想将 POOL.signUp(email, password...)
包装在 async
函数 sign_up
中,如下所示:
async function sign_up(email, password) {
POOL.signUp(email, password, [], null, function(err, result) {
console.log('...sign_up.result:', result);
return result;
})
};
async function main() {
let signupData = await sign_up(email, password);
console.log('...main.signupData:', signupData);
return signupData;
};
main().then((error, data) => {console.log('...error, data:', error, data)});
虽然它工作正常,但执行调用的顺序是错误的,因为 main
函数不等待 sign_up()
函数完成。为了纠正这种行为,我将 POOL.signUp(email, password...)
包装在 Promise:
中
async function sign_up(email, password) {
return await new Promise((resolve) => {
POOL.signUp(email, password, [], null, {
onSuccess: (result) => {
console.log('...result:', result)
return resolve(result);
},
onFailure: (err) => {
return resolve(err.message);
},
});
})
};
但我收到错误消息:
UnhandledPromiseRejectionWarning: TypeError: callback is not a function
有没有办法避免这个错误?
- 不需要
await
您返回的 Promise(因为我们恰恰希望我们的函数是异步的,我们希望将等待推迟到调用者)
Promise
构造函数需要提供第二个reject
参数才能在函数实现中访问回调
- 传递回调函数作为您的
POOL.signUp
第四个参数,而不是对象
function sign_up(email, password) {
return new Promise((resolve, reject) => {
POOL.signUp(email, password, [], null, function(err, result) {
if (err) {
return reject(err.message);
}
console.log('...result:', result)
resolve(result);
});
})
};
导出所需模块并设置变量后
let AWS = require("aws-sdk");
const AmazonCognitoIdentity = require('amazon-cognito-identity-js');
const USER_POOL_ID = 'us-east-1_vkXRQuP4U';
const CLIENT_ID = 'mipa4trls0l7323om33mlk80e8';
const poolData = {
UserPoolId : USER_POOL_ID, ClientId : CLIENT_ID
};
const POOL = new AmazonCognitoIdentity.CognitoUserPool(poolData);
let email = "my.email@domain.com";
let password = "My.Password!";
我可以继续调用 signUp
命令:
POOL.signUp(email, password, [], null, function(err, result) {
console.log('...result:', result);
});
而且效果很好。接下来我想将 POOL.signUp(email, password...)
包装在 async
函数 sign_up
中,如下所示:
async function sign_up(email, password) {
POOL.signUp(email, password, [], null, function(err, result) {
console.log('...sign_up.result:', result);
return result;
})
};
async function main() {
let signupData = await sign_up(email, password);
console.log('...main.signupData:', signupData);
return signupData;
};
main().then((error, data) => {console.log('...error, data:', error, data)});
虽然它工作正常,但执行调用的顺序是错误的,因为 main
函数不等待 sign_up()
函数完成。为了纠正这种行为,我将 POOL.signUp(email, password...)
包装在 Promise:
async function sign_up(email, password) {
return await new Promise((resolve) => {
POOL.signUp(email, password, [], null, {
onSuccess: (result) => {
console.log('...result:', result)
return resolve(result);
},
onFailure: (err) => {
return resolve(err.message);
},
});
})
};
但我收到错误消息:
UnhandledPromiseRejectionWarning: TypeError: callback is not a function
有没有办法避免这个错误?
- 不需要
await
您返回的 Promise(因为我们恰恰希望我们的函数是异步的,我们希望将等待推迟到调用者) Promise
构造函数需要提供第二个reject
参数才能在函数实现中访问回调- 传递回调函数作为您的
POOL.signUp
第四个参数,而不是对象
function sign_up(email, password) {
return new Promise((resolve, reject) => {
POOL.signUp(email, password, [], null, function(err, result) {
if (err) {
return reject(err.message);
}
console.log('...result:', result)
resolve(result);
});
})
};