在用户选择的工作日颤动重复警报

Question

如果我的用户设置了一些数据，例如：

day : "Sunday"
startTime: 8:00 A.M
endTime: 8:00 P.M
frequency: 30 minutes

我想从 8:00 A.M 开始每 30 分钟触发一次警报，所以 8:00 A.M、8:30 A.M、9:00 A.M、9:30 A.M ... .

现在我正在为我的应用程序使用 android_alarm_manager_plus，这是我到目前为止所做的：

AndroidAlarmManager.periodic(
   const Duration(minutes: 0, seconds: 1),
   0, 
   printHello, // callback function, for now I'm just printing "hello world"
);

如何在用户选择的日期、时间和频率设置闹钟？

更新 1：

AndroidAlarmManager.periodic(
   const Duration(minutes: _frequency!), //Evaluation of this constant expression throws an exception.
   0,
   printHello,
   startAt: DateTime(
     DateTime.now().year,
     DateTime.now().month,
     DateTime.now().day,
     _startTime, //The argument type 'TimeOfDay?' can't be assigned to the parameter type 'int'
     0,
   ),
);

我如何存储数据：

int? frequency;
TimeOfDay? startTime;

我的时间选择器：

  void selectStartTime() async {
    final TimeOfDay? newTime = await showTimePicker(
      context: context,
      initialTime: _startTime!,
      initialEntryMode: TimePickerEntryMode.input,
    );
    if (newTime != null) {
      setState(() {
        _startTime = newTime;
      });
    }
  }

更新 2： 好的，所以我检查了 android alarm manager plus 的源代码，我认为他们不支持我正在尝试做的事情开箱即用。

这是他们的周期性定时器的代码：

  static Future<bool> periodic(
    Duration duration,
    int id,
    Function callback, {
    DateTime? startAt,
    bool exact = false,
    bool wakeup = false,
    bool rescheduleOnReboot = false,
  }) async {
    // ignore: inference_failure_on_function_return_type
    assert(callback is Function() || callback is Function(int));
    assert(id.bitLength < 32);
    final now = _now().millisecondsSinceEpoch;
    final period = duration.inMilliseconds;
    final first =
        startAt != null ? startAt.millisecondsSinceEpoch : now + period;
    final handle = _getCallbackHandle(callback);
    if (handle == null) {
      return false;
    }
    final r = await _channel.invokeMethod<bool>('Alarm.periodic', <dynamic>[
      id,
      exact,
      wakeup,
      first,
      period,
      rescheduleOnReboot,
      handle.toRawHandle()
    ]);
    return (r == null) ? false : r;
  }

是否可以创建另一个自定义函数来执行我想要的操作？自定义函数看起来像这样：

  static Future<bool> customPeriodic(
    int id, // id
    Duration repeatAfter, // repeats after each m time(ex: 7 days)
    int frequency, // fire alarm after each n minutes(ex: 30 mins)
    Function callBack, {
    DateTime? startAt, // serve as start tune
    DateTime? endAt, // serve as end time
    bool exact = false,
    bool wakeup = false,
    bool rescheduleOnReboot = false,
  }) async {
    return true;
  }

Answer 1

添加startAt参数。在这段代码中，它将在当天早上 8 点开始。您可以随时更改为开始

AndroidAlarmManager.periodic(
   const Duration(minutes: 30), 0,
   printHello,
   startAt: DateTime(DateTime.now().year, DateTime.now().month, DateTime.now().day, 8, 0),
);

在用户选择的工作日颤动重复警报

Flutter repeat alarm on user selected week days

flutter

dart

android-alarms