如何将字符串(如"Sunday, July 4, 2021")解析为LocalDate?
How to parse string (such as "Sunday, July 4, 2021") to LocalDate?
我正在尝试将字符串 "Sunday, July 4, 2021"
解析为 LocalDate
,如下所示:
string this.selectedDate = "Sunday, July 4, 2021";
LocalDate date = LocalDate.parse(this.selectedDate);
但是我收到这个错误:
java.time.format.DateTimeParseException: Text 'Sunday, July 4, 2021' could not be parsed at index 0
如何将这样的字符串完整日期转换为 LocalDate?
像这样尝试。
String s = "Sunday, July 4, 2021";
DateTimeFormatter dtf = DateTimeFormatter.ofPattern("EEEE, LLLL d, yyyy");
LocalDate ld = LocalDate.parse(s, dtf);
System.out.println(ld);
打印
2021-07-04
如果您想更改输出格式,请继续阅读 DateTimeFormatter。
注意:如果月份的数字日期是星期几错误,您将得到解析错误。为避免这种情况,请跳过或忽略星期几。
我正在尝试将字符串 "Sunday, July 4, 2021"
解析为 LocalDate
,如下所示:
string this.selectedDate = "Sunday, July 4, 2021";
LocalDate date = LocalDate.parse(this.selectedDate);
但是我收到这个错误:
java.time.format.DateTimeParseException: Text 'Sunday, July 4, 2021' could not be parsed at index 0
如何将这样的字符串完整日期转换为 LocalDate?
像这样尝试。
String s = "Sunday, July 4, 2021";
DateTimeFormatter dtf = DateTimeFormatter.ofPattern("EEEE, LLLL d, yyyy");
LocalDate ld = LocalDate.parse(s, dtf);
System.out.println(ld);
打印
2021-07-04
如果您想更改输出格式,请继续阅读 DateTimeFormatter。
注意:如果月份的数字日期是星期几错误,您将得到解析错误。为避免这种情况,请跳过或忽略星期几。