具有目标值或键的对象的 jq 过滤器不存在

Question

我有 jsonlines 数据，想找到 1.value is empty object 或 2.key is not exist。在下面的示例中，我想知道 .items.spec.resource={} 或 .items.spec.limits| 请求哪个键不存在的项目的结果。

data='{"items":[{"metadata":{"name":"pod01"},"spec":{"containers":[{"name":"con01_01","resources":{"limits":{"cpu":"100m"},"requests":{"cpu":"100m"}}},{"name":"con01_02","resources":{"limits":{"cpu":"100m"},"requests":{"cpu":"100m"}}}]}},{"metadata":{"name":"pod02"},"spec":{"containers":[{"name":"con02_01","resources":{"limits":{"cpu":"100m"},"requests":{"cpu":"100m"}}},{"name":"con02_02","resources":{"limits":{"cpu":"100m"}}}]}},{"metadata":{"name":"pod03"},"spec":{"containers":[{"name":"con03_01","resources":{"limits":{"cpu":"100m"},"requests":{"cpu":"100m"}}},{"name":"con03_02","resources":{}}]}}]}'

list=$(echo $data | jq '.items[] | select(.spec.containers[].resources.requests == null or  .spec.containers[].resources.limits == null or .spec.containers[].resources == {})')

echo $list

结果出来了

{ 
  "metadata": { "name": "pod02" }, 
  "spec": { 
    "containers": [ 
      { "name": "con02_01", 
        "resources": { 
                       "limits": { "cpu": "100m" }, 
                       "requests": { "cpu": "100m" } 
                     } 
      }, 
      { "name": "con02_02", 
        "resources": { 
                       "limits": { "cpu": "100m" } 
                     } 
      } 
    ] 
  } 
} 
{ 
  "metadata": { "name": "pod03" },
  "spec": {
    "containers": [ 
      { 
        "name": "con03_01", 
        "resources": { 
                       "limits": { "cpu": "100m" }, 
                       "requests": { "cpu": "100m" } 
                     } 
      }, 
      { "name": "con03_02", 
        "resources": {} 
      } 
    ] 
  } 
} 

{ 
  "metadata": { "name": "pod03" }, 
  "spec": { 
    "containers": [ 
      { "name": "con03_01", 
        "resources": { 
                        "limits": { "cpu": "100m" }, 
                        "requests": { "cpu": "100m" } 
                     } 
      }, 
      { "name": "con03_02", 
        "resources": {} 
      } 
    ] 
  } 
} 
  
{ 
  "metadata": { "name": "pod03" }, 
  "spec": { 
    "containers": [ 
      { "name": "con03_01", 
        "resources": { 
                        "limits": { "cpu": "100m" }, 
                        "requests": { "cpu": "100m" } 
                      } 
      }, 
      { "name": "con03_02", 
        "resources": {} 
      } 
    ] 
  } 
}

repeat部分看不懂，估计是条件的问题，如何获取以上条件的部分，我想过滤metadata和spec.containers满足的部分条件。

Answer 1

根据您的解释性评论，您似乎可以使用 jq "$-variables" 实现您想要的：

jq -c '
.items[]
| .metadata.name as $podname
| .spec.containers[] 
| select(.resources.requests == null or 
         .resources.limits == null or 
         .resources == {})
| [$podname, .name]
'

根据您的数据，上面产生的输出将是：

["pod02","con02_02"]
["pod03","con03_02"]

简化

第三个条件（.resources == {}）的测试其实是多余的，所以上面的jq filter相当于：

.items[]
| .metadata.name as $podname
| .spec.containers[] 
| select(.resources | (.requests == null or .limits == null ))
| [$podname, .name]

存在密钥

要检查密钥是否存在，通常使用 has/1 是合适的，因为 {} | .key 的计算结果为 null。因此，您可能希望将上面的 select() 替换为：

select( any(.resources | has("requests", "limits"); not) )

具有目标值或键的对象的 jq 过滤器不存在

jq filter for object with target value or key is not exist

select

json

key

jq

jsonlines

简化

存在密钥